Chapter 9, Problem 47P

a.

To determine

Calculate the sample size for the population of Company J.

Answer to Problem 47P

The required sample size is 25 accounts using mean-per unit sampling.

Explanation of Solution

Sample size:

The sample size is the portion of the total population that represents the total population. The auditor conducts sampling test on the selected sample. Large sample size would represent the population more accurately but considering a large sample size would be a complex and expensive process. The auditor should select the sample size that would represent the entire population precisely and accurately.

Mean-per-unit sampling:

It is a technique of classical variables sampling. Mean-per-unit sampling works on the assumption that the audited mean of the sample size will represent the actual audited mean of the population. First, the mean of the sample size is calculated then the estimation for the value of the population is calculated by multiplying the calculated sample mean to the total of the items in the population. The difference between the value of the population calculated under mean-per unit sampling and the book value of the client is the projected misstatement.

Calculate the sample size for the population of Company J:

$\begin{array}{c}\text{Sample size = }{\left[\frac{\begin{array}{l}\text{Population size }\times \text{ (Incorrect acceptance coefficient}\\ \text{ + Incorrect rejected coefficient) }\times \text{ Estimated standard deviation}\end{array}}{\text{Tolerable misstatement}}\right]}^2\\ ={\left[\frac{\text{10,000 }\times \text{ (2 + 1}\text{.64) }\times \text{ \$25}}{\$182,000}\right]}^2\\ ={\left[\frac{\$910,000}{\$182,000}\right]}^2\\ =\text{ 25 accounts }\end{array}$

Thus, the required sample size is 25 accounts using mean-per unit sampling.

b.

To determine

Calculate the projected misstatement and provide an opinion whether the materially misstated account should be accepted or not.

Answer to Problem 47P

The projected misstatement is $30,000 and the auditor should accept that the account is not materially misstated.

Explanation of Solution

Material misstatement:

Risk assessment procedures performed by the auditors is aimed at identifying any misstated information in the financial statements that will lead to any fraud if not audited then it is called the material misstatement of financial records. Some matters are indispensable for the fair representation of the financial statements and to keep the financial statements free from any such material misstatement audit is performed.

Determine the projected misstatement in the population for Company J:

$\begin{array}{c}\text{Projected misstatement = Book value - Audited value}\\ \text{= \$1,250,000 - \$1,220,000 (1)}\\ \text{= \$30,000}\end{array}$

Thus, the projected misstatement is $30,000.

Working note 1:

Calculate the audited value:

$\begin{array}{c}\text{Total audited value of population= }\left[\begin{array}{c}\text{Sample mean }\\ \times \text{ Total number of the items in the population}\end{array}\right]\\ \text{= \$122 }\times \text{ 10,000}\\ \text{= \$1,220,000}\end{array}$

Provide an opinion whether the materially misstated account should be accepted or not:

Calculate the adjusted allowance for sampling risk:

$\begin{array}{c}\text{Allowable sampling risk = }\left(\begin{array}{c}\\ \text{Total misstatement - }\frac{\begin{array}{l}\text{Population size }\\ \times \text{ Incorrect acceptance coefficient }\\ \times \text{ Sample standard deviation}\end{array}}{\sqrt{\text{Sample size}}}\end{array}\right)\\ =\text{ \$182,000 - }\frac{\left(10,000\times \text{ 1}\text{.64 }\times \text{ 25}\right)}{\sqrt{25}}\\ =\text{ \$100,000}\end{array}$

Thus, the allowable sampling risk is  $100,000.

Suggest whether the auditor should accept the population or not:

The auditor should accept that the account is not materially misstated.

Calculate the confidence internal:

$\begin{array}{c}\text{Confidence interval = Projected misstatement }\pm \text{ Allowance for sampling risk}\\ \text{= \$30,000 }\pm \text{ \$100,000}\\ \text{= \$70,000 and \$130,000}\end{array}$

As the upper limit of confidence interval ($130,000) is not exceeding the tolerable misstatement (182,000) then the auditor should accept the population. The chances of excess misstatement are low with this population.

Thus, the auditor should accept that the account is not materially misstated.

c.

To determine

Calculate the projected misstatement and provide an opinion whether the materially misstated account should be accepted or not.

Answer to Problem 47P

The projected misstatement is $30,000 and the auditor should accept that the account is not materially misstated.

Explanation of Solution

Material misstatement:

Risk assessment procedures performed by the auditors is aimed at identifying any misstated information in the financial statements that will lead to any fraud if not audited then it is called the material misstatement of financial records. Some matters are indispensable for the fair representation of the financial statements and to keep the financial statements free from any such material misstatement audit is performed.

Determine the projected misstatement in the population for Company J:

$\begin{array}{c}\text{Projected misstatement = Book value - Audited value}\\ \text{= \$1,250,000 - \$1,220,000 (1)}\\ \text{= \$30,000}\end{array}$

Thus, the projected misstatement is $30,000.

Provide an opinion whether the materially misstated account should be accepted or not:

Calculate the adjusted allowance for sampling risk:

$\begin{array}{c}\text{Allowable sampling risk = }\left(\begin{array}{c}\\ \text{Total misstatement - }\frac{\begin{array}{l}\text{Population size }\\ \times \text{ Incorrect acceptance coefficient }\\ \times \text{ Sample standard deviation}\end{array}}{\sqrt{\text{Sample size}}}\end{array}\right)\\ =\text{ \$182,000 - }\frac{\left(10,000\times \text{ 1}\text{.64 }\times \text{ 20}\right)}{\sqrt{25}}\\ =\text{ \$116,400}\end{array}$

Thus, the allowable sampling risk is $116,400.

Suggest whether the auditor should accept the population or not:

The auditor should accept that the account is not materially misstated.

Calculate the confidence internal:

$\begin{array}{c}\text{Confidence interval = Projected misstatement }\pm \text{ Allowance for sampling risk}\\ \text{= \$30,000 }\pm \text{ \$116,400}\\ \text{= \$85,600 and \$146,400}\end{array}$

As the upper limit of confidence interval ($146,400) is not exceeding the tolerable misstatement (182,000) then the auditor should accept the population. The chances of excess misstatement are low with this population.

Thus, the auditor should accept that the account is not materially misstated.