Explanation Given data: Mass of the air-track ( m ) glider is 600 g, which is written as 0.6 Kg. Refer to the Figure P9.47 in the textbook for velocity of the glider and the force exerted by the spring on the glider. Formula used: Write the expression for impulse from impulse-momentum theorem. J → = p → f − p → i (1) Here, p → f is the final momentum of the particle, and p → i is the initial momentum of the particle. Write the expression for momentum of the particle in terms of velocity and mass. p → = m v → (2) Here, m is the mass of the particle, and v → is the velocity of the particle. Write the expression for impulse in terms of force and time period. J = F avg Δ t (3) Here, F avg is the force experienced by the particle in a particular interval of time period, and Δ t is the time interval. Explanation: From the Figure P9.47 in the textbook (first figure), the initial velocity of the glider ( v → i ) is ( − 3 ) m s and the final velocity of the glider is 3 m s . Modify the expression in equation (1) with the use of equation (2) as follows. J → = m v → f − m v → i = m ( v → f − v → i ) Substitute 0.6 Kg for m , ( − 3 ) m s for v → i , and 3 m s for v → f , J → = ( 0.6 Kg ) [ 3 m s − ( − 3 ) m s ] = ( 0

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ISBN: 9780134899978

Author: Knight

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Question

Chapter 9, Problem 47GP

To determine

To find: The time duration of the glider that in contact with the spring.

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Chapter 9, Problem 46GP

Chapter 9, Problem 48GP

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COLLEGE PHYSICS, VOL. 1-W/ACCESS

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