Explanation Given information: Given that the capacity of lake ( L ) is 1000 fish. Initial population of fish is 20 and growth constant ( k ) is 0.2 per day. Formula used: Logistic function is defined as f ( t ) = L 1 + e − k t C Where L = The curves maximum value k = Logistic growth constant t = Time period C = Arbitrary constant Calculation: Let y ( t ) be the fish population at any time t. Given fish population growth logistically so y ( t ) = 1000 1 − e − 0.2 t C ........ ( 1 ) Initially y ( 0 ) = 20 , y ( 0 ) = 1000 1 − e − 0

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ISBN: 9781319308858

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 9, Problem 47CRE

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To find the number of days for the fish population to reach 900 fish.

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CALCULUS:EARLY TRANS.(LL)-W/ACCESS

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To find the number of days for the fish population to reach 900 fish.

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