Chapter 9, Problem 42P

Part 2 (0.5 point) 0- Draw the major organic product with the correct geometry. 10 1: 70000 х く 1st attempt Part 1 (0.5 point) Feedback Please draw all four bonds at chiral centers. P See Periodic Table See Hint

Heating an alcohol in the presence of sulfuric or phosphoric acid will cause a dehydration to occur: the removal of the elements of water from a molecule, forming an alkene. The reaction usually follows an E1 mechanism. The SN1 pathway is suppressed by using a strong acid whose conjugate base is a poor nucleophile. Further, heating the reaction mixture causes a greater increase in the rate of E1 compared to the rate of S№1. 2nd attempt 0 See Periodic Table See Hint Draw the organic intermediate from the first step (no byproducts) and draw curved arrow(s) to show how it reacts. TH +11: 1st attempt Feedback H H H C F F See Periodic Table See Hint

This molecule undergoes an E1 mechanism when stirred in methanol. 3rd attempt CH₂OH CH₂OH 6148 O See Periodic Table. See Hint Draw 3 chemical species including formal charges and lone pairs of electrons. Add the missing curved arrow notation. H N O O SA 3 Br I

Complete the mechanism for the E1 reaction below by following the directions written above each of the five boxes. Be sure to include lone pair electrons and nonzero formal charges. 1st attempt Y 0 + Provide the missing curved arrow notation. 01: See Periodic Table See Hint H C Br I

Please help answer number 2. Thanks in advance.

How do I explain this? Thank you!

When an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M* = 163 m/z) is formed. In the infrared spectrum, important absorptions appear at 1661, 750 and 690 cm. The 13C NMR and DEPT spectra are provided. Draw the structure of the product as the resonance contributor lacking any formal charges. 13C NMR DEPT 90 200 160 120 80 40 0 200 160 120 80 40 0 DEPT 135 T 200 160 120 80 40 0 Draw the unknown amide. Select Dow Templates More Frage

Identify the unknown compound from its IR and proton NMR spectra. C4H6O: 'H NMR: 82.43 (1H, t, J = 2 Hz); 8 3.41 (3H, s); 8 4.10 (2H, d, J = 2 Hz) IR: 2125, 3300 cm¹ The C4H6O compound liberates a gas when treated with C2H5 MgBr. Draw the unknown compound. Select Draw с H Templates More

Please help with number 6 I got a negative number could that be right?