Explanation Given info: The mass of the man is 66 kg . There are 1208 nails in contact with the body of the man. The area of the ends of the nail is 1.00 × 10 − 6 m 2 . The total force exerted by all the nails on the man’s body is equal to the weight of the man. The force exerted by one nail will be, F = m g 1208 (1) m is the mass of the man g acceleration due to gravity The pressure exerted by each nail will be, P = F A (2) F is the force exerted by each nail A is the area of end of the nails Combining (1) in (2) to get the pressure exerted by each nail, P = m g 1208 A Substitute 66 kg for m , 1.00 × 10 − 6 m 2 for A , 9

Bundle: College Physics, Loose-Leaf Version, 10th, + WebAssign Printed Access Card for Serway/Vuille's College Physics, 10th Edition, Multi-Term

10th Edition

ISBN: 9781305367395

Author: Raymond A. Serway, Chris Vuille

Publisher: Cengage Learning

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Variation of pressure

From the equation of pressure, pressure is directly proportional to the applied force.

Question

Chapter 9, Problem 3WUE

To determine

The average pressure exerted by each nail on the man’s body.

Expert Solution & Answer

Chapter 9 Solutions

Bundle: College Physics, Loose-Leaf Version, 10th, + WebAssign Printed Access Card for Serway/Vuille's College Physics, 10th Edition, Multi-Term

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The average pressure exerted by each nail on the man’s body.

Solution Summary: The author calculates the average pressure exerted by each nail on the man's body.

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The average pressure exerted by each nail on the man’s body.

Chapter 9 Solutions