Explanation Formula used: For any triangle with sides a, b and c , opposite angles A , B and C respectively, the law of Cosines and law of Sines can be defined as follows. Law of cosines: a 2 = b 2 + c 2 − 2 b c cos A This can be also written as follows. b 2 = a 2 + c 2 − 2 a c cos B c 2 = a 2 + b 2 − 2 a b cos C Law of sines: a sin A = b sin B = c sin C Calculation: Given that, the magnitude of A = 43.12 ° , a = 7.893 and b = 4.113 . Sketch the graph of the triangle with known measures as shown below in Figure 1. From Figure 1, it is observed that the two sides and the opposite angle of larger side of the triangle are known. Therefore, there will be unique solution for this triangle. Now, use the law of sines and find the B . a sin A = b sin B 7.893 sin 43.12 ° = 4.113 sin B sin B = 4

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ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Chapter 9, Problem 36RE

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To solve: The triangle if A=43.12°,a=7.893 and b=4.113.

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Chapter 9, Problem 35RE

Chapter 9, Problem 37RE

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The triangle if A = 43.12 ° , a = 7.893 and b = 4.113 .

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To solve: The triangle if A=43.12°,a=7.893 and b=4.113.

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