To determine The original velocity of the lithium nucleus. Explanation Write the expression for velocity of the proton and helium nuclei along y axis, v L i y = m α v α − m p v p y m L i (I) Here, v L i y is the speed of the lithium particle along y axis, m L i is the mass of the lithium, v p y is the speed of the proton particle along y axis, m α is the mass of the alpha particle, v α is the speed of the alpha particle, and m p is the mass of the proton. The speed of the proton particle along y axis is, v p y = v p sin ϕ (II) Here, v p is the speed of the proton. Rewrite the equation (I) after substituting equation (II) in equation (I). v L i y = m α v α − m p v p sin ϕ m L i (III) Write the expression for velocity of the helium nuclei along the proton speed in x axis, v L i x = − m p v p x m L i (IV) Here, v L i x is the speed of the lithium particle along x axis and v p x is the speed of the proton along x axis. The speed of the proton particle along x axis is, v p x = v p cos ϕ (V) Rewrite the equation (IV) after substituting equation (V) in equation (IV). v L i x = − m p v p cos ϕ m L i (VI) Write the expression for total speed of the lithium. v L i = v L i x 2 + v L i y 2 (VII) Here, v L i is the original velocity of the lithium. Conclusion: Substitute 5.0 u for m L i , 1

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Chapter 9, Problem 34E

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The original velocity of the lithium nucleus.

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Chapter 9, Problem 33E

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