Java Programming (MindTap Course List)
Java Programming (MindTap Course List)
8th Edition
ISBN: 9781285856919
Author: Joyce Farrell
Publisher: Cengage Learning
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Chapter 9, Problem 2PE

a.

Explanation of Solution

Program:

File name: “MeanMedian.java

//Import necessary header files

import javax.swing.*;

//Define a class named MeanMedian

class MeanMedian

{

    //Define a main method

    public static void main(String[] args)

    {

        //Declare an array of nine integers

        int[] nums = new int[9];

        //Declare the variables and initialize the values

        String entry;

        String list = "You entered: ";

        int a, b;

        int temp;

        int midPos;

        int total = 0;

        double mean;

        //For loop to be executed until a exceeds 9

        for(a = 0; a < nums.length; ++a)

        {

            //Prompt the user to enter a number

            entry = JOptionPane.showInputDialog(null,

           "Enter number " + (a + 1));

            nums[a] = Integer.parseInt(entry);

            //Compute the total

            total += nums[a];

            //If a equals zero

            if(a == 0)

                //Find the list

                list += nums[a];

            //Else a not equals zero

            else

                //Find the list

                list += ",  " + nums[a];

        }

        //Print the result

        System...

b.

Explanation of Solution

Program:

File name: “MeanMedian2.java

//Import necessary header files

import javax.swing.*;

//Define a class named MeanMedian2

class MeanMedian2

{

    //Define a main method

    public static void main(String[] args)

    {

        //Declare an array of 20 integers

        int[] nums = new int[20];

        //Declare the variables and initialize the values

        int num = 0;

        String entry;

        String list = "You entered: ";

        int a, b;

        int temp;

        double median;

        int total = 0;

        double mean = 0;

        final int QUIT = 9999;

        int size = 0;

        /*For loop to be executed until a exceeds 20 and does not enter QUIT*/

        for(a = 0; num != QUIT && a < nums.length; ++a)

        {

            //Prompt the user to enter a number or QUIT

            entry = JOptionPane.showInputDialog(null,

"Enter number " + (a + 1) + " or " + QUIT + " to quit");

            num = Integer.parseInt(entry);

            //If the user does not enter QUIT

            if(num != QUIT)

            {

                //Assign the value

                nums[a] = num;

                //Find the total

                total += nums[a];

                //If a equals zero

                if(a == 0)

                    //Find the list

                    list += nums[a];

                //Else

                else

                    //Find the list

                    list += ",  " + nums[a];

            }

        }

        //Print the result

        System.out.println("size is " + a);

        //If the user does not enter QUIT

        if(num != QUIT)

            //Find the size

            size = nums...

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Students have asked these similar questions
7. See the code below and solve the following. public class Test { public static void main(String[] args) { int result = 0; } result = fn(2,3); System.out.println("The result is: + result); // fn(x, 1) = x // fn(x, y) = fn(x, y-1) + 2, when y>1 public static int fn(int x, int y) { if (x <= 1) return x; else return fn(x, y-1) + 2; } } 7-1. This program has a bug that leads to infinite recursion. Modify fn(int x, int y) method to fix the problem. (2 point) 7-2. Manually trace the recursive call, fn(2,3) and show the output (step by step). (2 point) 7-3. Can you identify the Base Case in recursive method fn(int x, int y)? (1 point)
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Write a program that reads a list of integers from input and determines if the list is a palindrome (values are identical from first to last and last to first). The input begins with an integer indicating the length of the list that follows. Assume the list will contain a maximum of 20 integers. Output "yes" if the list is a palindrome and "no" otherwise. The output ends with a newline. Hints:   - use a for loop to populate the array based on the specified size (the first number entered)              - use a for loop to check first value with last value, second value with second from end, etc.              - if the values do not match, set a Boolean variable to flag which statement to output (yes or no)   Ex: If the input is (remember to include spaces between the numbers): 6 1 5 9 9 5 1 the output is: yes Ex: If the input is: 5 1 2 3 4 5 the output is: C++ coding
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