Explanation Formula used: “Let A be the area of the area of the base and h be the height then the volume of the prism is given by: V = A h Let l be the length and b be the breadth of the rectangle, then area of the rectangle is given by the formula: A = l ⋅ b The density is given by the formula: Density = Weight Volume ” Given: The linear speed at which the conveyor moves as 360 ft/min , weight of one bushel of oats as 32 lb , and the density of oats as 25.6 lb cu ft . Also it is to be noted that, the oats are moving along the 12 in width of the conveyor at an average height of 4 in. Calculation: It is known that, 1 hr = 60 min . Calculate the total length of the belt moved in an hour at 360 ft/min as follows: 360 ft min × 60 min = 21 , 600 ft Therefore, the length of the belt moved in an hour is 21600 ft. It is known that, 1 ft = 12 in . . Therefore, the given width in feet is 1 ft. Convert the height in inches to feet as shown below: 1 ft = 12 in . ( Divide both sides by 12 ) 1 12 ft = 12 12 in . 1 12 ft = 1 in . ( Multiply both sides by 4 ) 4 12 ft = 4 in . 1 3 ft ≈ 4 in . Substitute the values l = 21 , 600 ft and b = 1 ft in the formula A = l ⋅ b and calculate the area of the conveyor as shown below: A = l ⋅ b = 21 , 600 ⋅ 1 = 21 , 600 sq ft Thus, the area of the conveyor is 21,600 sq ft. Substitute the values A = 21 , 600 sq ft and h = 1 3 in

Mathematics for the Trades: A Guided Approach (11th Edition) (What's New in Trade Math)

11th Edition

ISBN: 9780134756967

Author: Hal Saunders, Robert Carman

Publisher: PEARSON

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Chapter 9, Problem 28BPS

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The number of bushels of oats the grain conveyor unloaded in an hour.

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Chapter 9, Problem 27BPS

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Chapter 9 Solutions

Mathematics for the Trades: A Guided Approach (11th Edition) (What's New in Trade Math)

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The number of bushels of oats the grain conveyor unloaded in an hour.

Solution Summary: The author calculates the total length of the belt moved in an hour at 360ft/min.

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The number of bushels of oats the grain conveyor unloaded in an hour.

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Chapter 9 Solutions