Consider a system of two particles in the xy plane: m1 = 2.00 kg is at the location
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Physics for Scientists and Engineers with Modern Physics
- A small ball of mass mb = 0.050 kg is projected into a pendulum of mass Mp = 0.200 kg in a ballistic pendulum experiment. How fast does the ball need to go in order to get the pendulum to swing up to a height of h = 0.25 m abov its original position? O 11.1 m/s 0.553 m/s 2.21 m/s 0.111 m/sarrow_forwardConsider a system of two particles in the xy-plane. For the first particle, Its mass is m₁ = 1.30 kg Its position is 7¹₁ = (1.202 + 2.203) m Its velocity is ₁ = (2.2002 + 0.100)) m/s For the second particle, Its mass is m₂ = 2.90 kg Its position is 7¹2 = (-3.60% - 2.403) m Its velocity is v₂ = (2.2001 - 2.000)) m/s a. Find the position of the center of mass of the system. 7CM = im+m b. Determine the velocity of the center of mass. UCM = 2 m/s + m/s c. What is the total linear momentum of the system? Pr = kg-m/s + kg-m/sarrow_forwardA man (weighing 915 N) stands on a long railroad flatcar (weighing 2415 N) as it rolls at 18.2 m/s in the positive direction of an x axis, with negligible friction.Then the man runs along the flatcar in the negative x direction at 4.00 m/s relative to the flatcar. What is the resulting increase in the speed of the flatcar?arrow_forward
- The mass of particle 1 is 11kg. The initial velocity for particle 1 is (-104m/s)i + (216m/s)j. F21 = Fxe^-(t/T) + Fysin(2pit/T). Only need help finding the displacement of particle 1 in the x and y directions.arrow_forwardA small ball of mass mb = 0.050 kg is projected into a pendulum of mass Mp = 0.200 kg in a ballistic pendulum experiment. How fast does the ball need to go in order to get the pendulum to swing up to a height of h = 0.25 m above its original position? 2.21 m/s 0.111 m/s 11.1 m/s 0.553 m/sarrow_forwardA pendulum of length L = 1.0 meter and bob of mass m = 1.0 kg is released from rest at an angle θ = 30 degrees. When the pendulum reaches the vertical position, the bob strikes a cube with mass M = 3.0 kg that is resting on a frictionless table of height h = 0.85 m. d. Determine how far away from the bottom edge of the table, Δx, the cube will strike the floor e. At the location where the cube would have struck the floor, there is now a small cart of mass M = 3.0 kg and negligible height. The cube lands on the cart, and sticks to the cart in a completely *inelastic* collision. Ignore friction. Calculate the horizontal velocity of the cart just after the cube lands on it.arrow_forward
- Consider a system of two particles in the xy plane: m1 = 2.00 kgis at the location r→1 = (1.00î + 2.00ĵ)m and has a velocity of (3.00î + 0.500ĵ)m/s; m2 = 3.00 kg is at r→2 = (-4.00î - 3.00ĵ)m and has velocity (3.00î- 2.00ĵ) m/s. (a) Plot these particles on a grid or graph paper. Draw their position vectors and show their velocities. (b) Find the position of the center of mass of the system and mark it on the grid. (c) Determine the velocity of the center of mass and also show it on the diagram. (d) What is the total linear momentum of the system?arrow_forwardCalculate the kinetic energies (in J) of the following. (a) a 2,001.0 kg automobile moving at 130.0 km/h J (b) an 83 kg runner sprinting at 13 m/s J (c) a 9.1 ✕ 10−31 kg electron moving at 2.1 ✕ 107 m/s Jarrow_forwardA 5.27-kg object passes through the origin at time t = 0 such that its x component of velocity is 5.40 m/s and its y component of velocity is -3.15 m/s. (a) What is the kinetic energy of the object at this time? 102.93 (b) At a later time t = 2.00 s, the particle is located at x = 8.50 m and y = 5.00 m. What constant force acted on the object during this time interval? 6.96 X magnitude Your response differs from the correct answer by more than 10%. Double check your calculations. N º measured from the +x axis direction (c) What is the speed of the particle at t = 2.00 s? m/s Additional Materials eBookarrow_forward
- The carbon isotope 14C is used for carbon dating of archeological artifacts. 14C (mass 2.34 x 10-26 kg) decays by the process known as beta decay in which the nucleus emits an electron (the beta particle) and a subatomic particle called a neutrino. In one such decay, the electron and the neutrino are emitted at right angles to each other. The electron (mass 9.11 x 10-31 kg) has a speed of 5.00 x 107 m/s and the neutrino has a momentum of 8.00 x 10-24 kg • m/s. What is the recoil speed of the nucleus?arrow_forward= 1. Sphere A has mass ma = 0.05 kg, velocity magnitude va = 2.0 m/s making an angle 30° with the + axis. Sphere B has mass m₁ = 0.03 kg, velocity magnitude Vb = 3.0 m/s and moves along the +y axis. Sphere C has mass mc 0.04 kg, velocity magnitude vc = 4.0 m/s and moves along the +x axis. See figure. They are all approaching the origin as they slide on a frictionless surface. The three spheres arrive at the origin at the same time and stick together. (a) What is the final velocity of the combined object? (b) How does the final kinetic energy compare to the kinetic energy before the collision? y m a m mb Xarrow_forwardA ball, mi1 = 0.250kg, slides on a frictionless surface into a dark room where it strikes an initially stationary second ball, m2= 0.400kg. The initial velocity of mi is 2.00 m/s and it is traveling 1.5m/s at an angle of 28° relative to its original direction after the collision. Ignoring friction and rotational motion, find the magnitude and direction of the second ball's velocity. VIf Vli V2farrow_forward
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