Foundations of College Chemistry, Binder Ready Version
Foundations of College Chemistry, Binder Ready Version
15th Edition
ISBN: 9781119083900
Author: Morris Hein, Susan Arena, Cary Willard
Publisher: WILEY
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Chapter 9, Problem 25PE

(a)

Interpretation Introduction

Interpretation:

The limiting reactant and the number of moles aluminum sulfate produced have to be given.

Concept Introduction:

The limiting reactant of the reaction is the reactant that is completely used during the reaction.  Using the mole ratio and starting amounts of the reactants limiting reactant can be determined.

Example:

Consider a reaction starts with 30g CaCO3&11gHCl. The values in grams has to be converted to moles by dividing with their molecular weights.  According to the mole ratio 0.3g of calcium carbonate require 0.6g of HCl completely.  Therefore HCl is the limiting agent.

(a)

Expert Solution
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Explanation of Solution

Given,

The mass of Al(OH)3 is 35g.

The mass of H2SO4 is 35g.

The molecular weight of Al(OH)3 is 78g/mol.

The molecular weight of H2SO4 is 98.07g/mol.

The molecular weight of Al2(SO4)3 is 342.15g/mol.

The given reaction is,

  2Al(OH)3+3H2SO4Al2(SO4)3+6H2O

The limiting reactant can be given by finding the mass of the product.

The moles of Al2(SO4)3 from Al(OH)3 can be calculated as,

  35gAl(OH)3(1molAl(OH)378gAl(OH)3)(1molAl2(SO4)32molAl(OH)3)=0.2243molAl2(SO4)3

The moles of Al2(SO4)3 from H2SO4 can be calculated as,

  35gH2SO4(1molH2SO498.07gH2SO4)(1molAl2(SO4)33molH2SO4)=0.1189molAl2(SO4)3

The moles of Al2(SO4)3 from aluminum hydroxide is 0.2243mol.

The moles of Al2(SO4)3 from sulfuric acid is 0.1189mol.

Since H2SO4 produces less Al2(SO4)3, H2SO4 is the limiting reactant.

(b)

Interpretation Introduction

Interpretation:

The grams of aluminum sulfate produced and the excess reactant has to be given.

(b)

Expert Solution
Check Mark

Explanation of Solution

Given,

The mass of Al(OH)3 is 25g.

The mass of H2SO4 is 45g.

The molecular weight of Al(OH)3 is 78g/mol.

The molecular weight of H2SO4 is 98.07g/mol.

The molecular weight of Al2(SO4)3 is 342.15g/mol.

The given reaction is,

  2Al(OH)3+3H2SO4Al2(SO4)3+6H2O

The excess reactant can be given by finding the mass of the product.

The mass of Al2(SO4)3 from Al(OH)3 can be calculated as,

  25gAl(OH)3(1molAl(OH)378gAl(OH)3)(1molAl2(SO4)32molAl(OH)3)(342.15gAl2(SO4)31mol)=54.83gAl2(SO4)3

The mass of Al2(SO4)3 from H2SO4 can be calculated as,

  45gH2SO4(1molH2SO498.07gH2SO4)(1molAl2(SO4)33molH2SO4)(342.15gAl2(SO4)31mol)=52.3gAl2(SO4)3

The mass of Al2(SO4)3 from aluminum hydroxide is 54.83g.

The mass of Al2(SO4)3 from sulfuric acid is 52.3g.

Since H2SO4 produces less Al2(SO4)3, H2SO4 is the limiting reactant and Al(OH)3 is the excess reactant.

(c)

Interpretation Introduction

Interpretation:

The number of moles of substance present in the container after the completion of reaction and the substance that will be present in the container has to be given.

(c)

Expert Solution
Check Mark

Explanation of Solution

Given,

The number of moles of Al(OH)3 is 2.5mol.

The number of moles of H2SO4 is 5.5mol.

The given reaction is,

  2Al(OH)3+3H2SO4Al2(SO4)3+6H2O

The moles of Al2(SO4)3 from Al(OH)3 can be calculated as,

  2.5molAl(OH)3(1molAl2(SO4)32molAl(OH)3)=1.25 molAl2(SO4)3

The number of moles of unreacted H2SO4 is 5.5-1.25=4.25mol

When the reaction is completed 1.25mol of Al(OH)3 is produced and 4.25mol of H2SO4 is unreacted and it will be present inside the container.

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Interpreting NMR spectra is a skill that often requires some amount of practice, which, in turn, necessitates access to a collection of NMR spectra. Beyond Labz Organic Synthesis and Organic Qualitative Analysis have spectral libraries containing over 700 1H NMR spectra. In this assignment, you will take advantage of this by first predicting the NMR spectra for two closely related compounds and then checking your predictions by looking up the actual spectra in the spectra library. After completing this assignment, you may wish to select other compounds for additional practice. 1. Write the IUPAC names for the following two structures: Question 2 Question 3 2. Predict the NMR spectra for each of these two compounds by listing, in the NMR tables below, the chemical shift, the splitting, and the number of hydrogens associated with each predicted peak. Sort the peaks from largest chemical shift to lowest. **Not all slots must be filled**
11:14 ... worksheets.beyondlabz.com 3. To check your predictions, click this link for Interpreting NMR Spectra 1. You will see a list of all the - compounds in the spectra library in alphabetical order by IUPAC name. Hovering over a name in the list will show the structure on the chalkboard. The four buttons on the top of the Spectra tab in the tray are used to select the different spectroscopic techniques for the selected compound. Make sure the NMR button has been selected. 4. Scroll through the list of names to find the names for the two compounds you have been given and click on the name to display the NMR spectrum for each. In the NMR tables below, list the chemical shift, the splitting, and the number of hydrogens associated with each peak for each compound. Compare your answers to your predictions. **Not all slots must be filled** Peak Chemical Shift (d) Multiplicity 1 2 3 4 5
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