Explanation The dipole moment would be equal to the product of charge and the distance between the charges. For the distance of 100 pm: The charge of a proton is equal to 1.6 × 10 − 19 C and that of an electron is − 1.6 × 10 − 19 C . Hence, the dipole moment would be equal to p = ( 1.6 × 10 − 19 ) · ( 100 × 10 − 12 ) = 1.6 × 10 − 22 C m .The dipole moment value is equal to 1.6 × 10 − 22 C m . For the distance of 200 pm: To determine: The magnitude of the dipole moment formed by separating a proton and an electron by 200 pm

Masteringchemistry with Pearson Etext -- Standalone Access Card -- For Chemistry

3rd Edition

ISBN: 9780321806383

Author: Nivaldo J. Tro

Publisher: PEARSON

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Chapter 9, Problem 23E

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To determine: The magnitude of the dipole moment formed by separating a proton and an electron by 100 pm and 200 pm.

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Chapter 9, Problem 22E

Chapter 9, Problem 24E

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Masteringchemistry with Pearson Etext -- Standalone Access Card -- For Chemistry

Ch. 9 - Prob. 1SAQ Ch. 9 - Q2. Which set of elements is arranged in order of...Ch. 9 - Q3. Which is the correct Lewis structure for...Ch. 9 - Q4. Which compound is likely to have an incomplete...Ch. 9 - Q5. Which compound has the highest magnitude of...Ch. 9 - Prob. 6SAQ Ch. 9 - Prob. 7SAQ Ch. 9 - Prob. 8SAQ Ch. 9 - Prob. 9SAQ Ch. 9 - Prob. 10SAQ

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