Loose Leaf for Statistical Techniques in Business and Economics
17th Edition
ISBN: 9781260152647
Author: Douglas A. Lind
Publisher: McGraw-Hill Education
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Question
Chapter 9, Problem 1SR
a.
To determine
Find the population
a.
Expert Solution
Explanation of Solution
Here, the sample mean is provided and there is no information about the population mean of daily sales for Bun-and-Run franchise.
b.
To determine
Find the best estimate of the population mean.
b.
Expert Solution
Answer to Problem 1SR
The best estimate of the population mean is $20,000.
Explanation of Solution
Calculation:
The sample mean is the point estimate of the population mean. Moreover, the sample statistic gives the best estimate for the population parameter.
Here, the sample mean is $20,000. Hence, the point estimate of the population mean is $20,000. That is, the best estimate for the population mean is the sample mean, which is denoted as
c.
To determine
Find the 95% confidence interval for the population mean of daily sales.
c.
Expert Solution
Answer to Problem 1SR
The 95% confidence interval for the population mean of daily sales is
Explanation of Solution
Calculation:
Step-by-step procedure to obtain the confidence interval using MINITAB software is given below:
- Choose Stat > Basic Statistics > 1-Sample Z.
- In Summarized data, enter the
sample size as 40 and mean as 20,000. - In Standard deviation, enter 3,000.
- Check Options, enter Confidence level as 95.
- Choose Mean ≠ Hypothesized mean in alternative.
- Click OK in all dialogue boxes.
Output using MINITAB software is given below:
From the MINITAB output, the 95% confidence interval for the population mean of daily sales is
d.
To determine
Interpret the confidence interval in Part (c).
d.
Expert Solution
Explanation of Solution
Interpretation:
There is 95% confidence that the population mean of daily sales lies between $19,070 and $20,930.
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Students have asked these similar questions
(a) Test the hypothesis.
Consider the hypothesis test Ho
=
:
against H₁o < 02. Suppose that the sample sizes aren₁ =
7 and n₂
= 13 and that
$²
= 22.4 and $22
= 28.2. Use α = 0.05.
Ho
is not
✓ rejected.
9-9
IV
(b) Find a 95% confidence interval on of 102. Round your answer to two decimal places (e.g. 98.76).
Let us suppose we have some article reported on a study of potential sources of injury to equine veterinarians conducted at a
university veterinary hospital. Forces on the hand were measured for several common activities that veterinarians engage in when
examining or treating horses. We will consider the forces on the hands for two tasks, lifting and using ultrasound. Assume that both
sample sizes are 6, the sample mean force for lifting was 6.2 pounds with standard deviation 1.5 pounds, and the sample mean force
for using ultrasound was 6.4 pounds with standard deviation 0.3 pounds. Assume that the standard deviations are known.
Suppose that you wanted to detect a true difference in mean force of 0.25 pounds on the hands for these two activities. Under the null
hypothesis, 40 = 0. What level of type II error would you recommend here?
Round your answer to four decimal places (e.g. 98.7654). Use a
= 0.05.
β
= i
What sample size would be required?
Assume the sample sizes are to be equal.…
=
Consider the hypothesis test Ho: μ₁ = μ₂ against H₁ μ₁ μ2. Suppose that sample sizes are n₁ =
15 and n₂ =
15, that x1 = 4.7
and X2 = 7.8 and that s² = 4 and s² = 6.26. Assume that o and that the data are drawn from normal distributions. Use
απ 0.05.
(a) Test the hypothesis and find the P-value.
(b) What is the power of the test in part (a) for a true difference in means of 3?
(c) Assuming equal sample sizes, what sample size should be used to obtain ẞ = 0.05 if the true difference in means is - 2? Assume
that α = 0.05.
(a) The null hypothesis is
98.7654).
rejected. The P-value is 0.0008
(b) The power is 0.94
. Round your answer to four decimal places (e.g.
Round your answer to two decimal places (e.g. 98.76).
(c) n₁ = n2 =
1
. Round your answer to the nearest integer.
Chapter 9 Solutions
Loose Leaf for Statistical Techniques in Business and Economics
Ch. 9 - Prob. 1SRCh. 9 - Prob. 1ECh. 9 - A sample of 81 observations is taken from a normal...Ch. 9 - Prob. 3ECh. 9 - Suppose you know and you want an 85% confldence...Ch. 9 - Prob. 5ECh. 9 - Prob. 6ECh. 9 - Prob. 7ECh. 9 - Prob. 8ECh. 9 - Prob. 2SR
Ch. 9 - Prob. 9ECh. 9 - Prob. 10ECh. 9 - Prob. 11ECh. 9 - Prob. 12ECh. 9 - Prob. 13ECh. 9 - Prob. 14ECh. 9 - Prob. 3SRCh. 9 - Prob. 15ECh. 9 - Ms. Maria Wilson is considering running for mayor...Ch. 9 - Prob. 17ECh. 9 - Prob. 18ECh. 9 - Prob. 4SRCh. 9 - Prob. 19ECh. 9 - Prob. 20ECh. 9 - Prob. 21ECh. 9 - Prob. 22ECh. 9 - Prob. 23ECh. 9 - Prob. 24ECh. 9 - Prob. 25ECh. 9 - Prob. 26ECh. 9 - The same study of church contributions in Scandia...Ch. 9 - Thirty-six items are randomly selected from a...Ch. 9 - Forty-nine items are randomly selected from a...Ch. 9 - The attendance at the Savannah Colts minor league...Ch. 9 - There are 300 welders employed at Maine Shipyards...Ch. 9 - Prob. 31CECh. 9 - Prob. 32CECh. 9 - Prob. 33CECh. 9 - Prob. 34CECh. 9 - Prob. 35CECh. 9 - Prob. 36CECh. 9 - Prob. 37CECh. 9 - Prob. 38CECh. 9 - Prob. 39CECh. 9 - Prob. 40CECh. 9 - Prob. 41CECh. 9 - Prob. 42CECh. 9 - Prob. 43CECh. 9 - Prob. 44CECh. 9 - Prob. 45CECh. 9 - Prob. 46CECh. 9 - Prob. 47CECh. 9 - Prob. 48CECh. 9 - Prob. 49CECh. 9 - Prob. 50CECh. 9 - Prob. 51CECh. 9 - Prob. 52CECh. 9 - Prob. 53CECh. 9 - Prob. 54CECh. 9 - Prob. 55CECh. 9 - Prob. 56CECh. 9 - Prob. 57CECh. 9 - Prob. 58CECh. 9 - Prob. 59CECh. 9 - Prob. 60CECh. 9 - Prob. 61CECh. 9 - Prob. 62CECh. 9 - Prob. 63CECh. 9 - Prob. 64CECh. 9 - Prob. 65CECh. 9 - Prob. 66CECh. 9 - A sample of 352 subscribers to Wired magazine...Ch. 9 - Prob. 68CECh. 9 - Prob. 70DACh. 9 - Prob. 1PCh. 9 - Prob. 2PCh. 9 - Prob. 3PCh. 9 - Prob. 4PCh. 9 - Prob. 5PCh. 9 - Prob. 6PCh. 9 - Prob. 7PCh. 9 - Prob. 8PCh. 9 - Prob. 9PCh. 9 - Prob. 10PCh. 9 - Prob. 11PCh. 9 - Prob. 12PCh. 9 - Prob. 13PCh. 9 - Prob. 1CCh. 9 - Prob. 1.1PTCh. 9 - Prob. 1.2PTCh. 9 - Prob. 1.3PTCh. 9 - Prob. 1.4PTCh. 9 - Prob. 1.5PTCh. 9 - Prob. 1.6PTCh. 9 - Prob. 1.7PTCh. 9 - Prob. 1.8PTCh. 9 - Prob. 1.9PTCh. 9 - Prob. 1.10PTCh. 9 - Prob. 2.1PTCh. 9 - Prob. 2.2PTCh. 9 - Prob. 2.3PTCh. 9 - Prob. 2.4PT
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