Modern Physics, 3rd Edition
3rd Edition
ISBN: 9780534493394
Author: Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher: Cengage Learning
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Question
Chapter 9, Problem 1Q
To determine
The reason behind the opposite direction of orbital
Expert Solution & Answer
Answer to Problem 1Q
The direction of magnetic moment and orbital angular momentum of a charged particle depends upon the polarity of the charge on the charged particle. The electron is a negatively charged particle due to which the direction of magnetic moment is opposite to that of the direction of orbital angular momentum.
Explanation of Solution
The orbital angular moment of an electron arises due to the motion of the electron about its nucleus. The orbital angular momentum is rotational variant of linear angular momentum.
The magnetic moment or magnetic dipole moment of an electron arises due to the intrinsic properties of electron mainly charge and spin.
Write the expression for the magnetic moment of a charged particle.
Here,
The direction of magnetic moment and orbital angular momentum of a charged particle depends upon the polarity of the charge on the charged particle. The electron is a negatively charged particle due to which the direction of magnetic moment is opposite to that of the direction of orbital angular momentum.
Conclusion:
Thus, the direction of magnetic moment and orbital angular momentum of a charged particle depends upon the polarity of the charge on the charged particle. The electron is a negatively charged particle due to which the direction of magnetic moment is opposite to that of the direction of orbital angular momentum.
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Chapter 9 Solutions
Modern Physics, 3rd Edition
Ch. 9.2 - Prob. 1ECh. 9.3 - Prob. 2ECh. 9 - Prob. 1QCh. 9 - Prob. 2QCh. 9 - Prob. 3QCh. 9 - Prob. 4QCh. 9 - Prob. 5QCh. 9 - Prob. 6QCh. 9 - Prob. 7QCh. 9 - Prob. 8Q
Ch. 9 - Prob. 9QCh. 9 - Prob. 11QCh. 9 - For a one-electron atom or ion, spinorbit coupling...Ch. 9 - Prob. 14QCh. 9 - Prob. 1PCh. 9 - Prob. 2PCh. 9 - Prob. 4PCh. 9 - The force on a magnetic moment z in a nonuniform...Ch. 9 - Consider the original Stern–Gerlach experiment...Ch. 9 - Prob. 7PCh. 9 - Consider a right circular cylinder of radius R,...Ch. 9 - Prob. 9PCh. 9 - Prob. 10PCh. 9 - Prob. 11PCh. 9 - Prob. 12PCh. 9 - Prob. 13PCh. 9 - Prob. 14PCh. 9 - Prob. 15PCh. 9 - Prob. 16PCh. 9 - Prob. 17PCh. 9 - Prob. 18PCh. 9 - Prob. 21PCh. 9 - Prob. 22PCh. 9 - Prob. 23PCh. 9 - Prob. 24PCh. 9 - Prob. 25P
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