Big Java Late Objects
2nd Edition
ISBN: 9781119330455
Author: Horstmann
Publisher: WILEY
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Expert Solution & Answer
Chapter 9, Problem 14RE
a.
Explanation of Solution
Given:
//Create an object
Sandwich sub = new Sandwich();
//Create an object
Rectangle cerealBox = new Rectangle(5, 10, 20, 30);
//Assign null value
Edible e = null;
“e = sub;”:
The given assignment statement is legal.
Justification:
- One can convert from a class type to any interface type that the class implements...
b.
Explanation of Solution
Given:
//Create an object
Sandwich sub = new Sandwich();
//Create an object
Rectangle cerealBox = new Rectangle(5, 10, 20, 30);
//Assign null value
Edible e = null;
“sub = e;”:
The given assignment statement is illegal.
Justification:
- One can convert from a class type to any interface type that the class implements.
- Given that the class “Sandwich” implements an interface “Edible”...
c.
Explanation of Solution
Given:
//Create an object
Sandwich sub = new Sandwich();
//Create an object
Rectangle cerealBox = new Rectangle(5, 10, 20, 30);
//Assign null value
Edible e = null;
“sub = (Sandwich) e;”:
The given assignment statement is legal.
Justification:
- Given that the class “Sandwich” implements an interface “Edible”.
- “sub” is an instance variable of “Sandwich” class, and “e” is a variable of “Edible” interface...
d.
Explanation of Solution
Given:
//Create an object
Sandwich sub = new Sandwich();
//Create an object
Rectangle cerealBox = new Rectangle(5, 10, 20, 30);
//Assign null value
Edible e = null;
“sub = (Sandwich) cerealBox;”:
The given assignment statement is legal.
Justification:
- Given that the class “Sandwich” implements an interface “Edible”...
e.
Explanation of Solution
Given:
//Create an object
Sandwich sub = new Sandwich();
//Create an object
Rectangle cerealBox = new Rectangle(5, 10, 20, 30);
//Assign null value
Edible e = null;
“e = cerealBox;”:
The given assignment statement is illegal.
Justification:
- Given that the class “Sandwich” implements an interface “Edible”...
f.
Explanation of Solution
Given:
//Create an object
Sandwich sub = new Sandwich();
//Create an object
Rectangle cerealBox = new Rectangle(5, 10, 20, 30);
//Assign null value
Edible e = null;
“e = (Edible) cerealBox;”:
The given assignment statement is legal.
Justification:
- Given that the class “Sandwich” implements an interface “Edible”...
g.
Explanation of Solution
Given:
//Create an object
Sandwich sub = new Sandwich();
//Create an object
Rectangle cerealBox = new Rectangle(5, 10, 20, 30);
//Assign null value
Edible e = null;
“e = (Rectangle) cerealBox;”:
The given assignment statement is illegal.
Justification:
- Given that the class “Sandwich” implements an interface “Edible”...
h.
Explanation of Solution
Given:
//Create an object
Sandwich sub = new Sandwich();
//Create an object
Rectangle cerealBox = new Rectangle(5, 10, 20, 30);
//Assign null value
Edible e = null;
“e = (Rectangle) null;”:
The given assignment statement is illegal...
Expert Solution & Answer
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Chapter 9 Solutions
Big Java Late Objects
Ch. 9.1 - Prob. 1SCCh. 9.1 - Prob. 2SCCh. 9.1 - Prob. 3SCCh. 9.1 - Prob. 4SCCh. 9.1 - Prob. 5SCCh. 9.2 - Prob. 6SCCh. 9.2 - Prob. 7SCCh. 9.2 - Prob. 8SCCh. 9.2 - Prob. 9SCCh. 9.2 - Prob. 10SC
Ch. 9.3 - Prob. 11SCCh. 9.3 - Prob. 12SCCh. 9.3 - Prob. 13SCCh. 9.3 - Prob. 14SCCh. 9.3 - Prob. 15SCCh. 9.4 - Prob. 16SCCh. 9.4 - Prob. 17SCCh. 9.4 - Prob. 18SCCh. 9.4 - Prob. 19SCCh. 9.4 - Prob. 20SCCh. 9.5 - Prob. 21SCCh. 9.5 - Prob. 22SCCh. 9.5 - Prob. 23SCCh. 9.5 - Prob. 24SCCh. 9.5 - Prob. 25SCCh. 9.6 - Prob. 26SCCh. 9.6 - Prob. 27SCCh. 9.6 - Prob. 28SCCh. 9.6 - Prob. 29SCCh. 9.6 - Prob. 30SCCh. 9.6 - Prob. 31SCCh. 9 - Prob. 1RECh. 9 - Prob. 2RECh. 9 - Prob. 3RECh. 9 - Prob. 4RECh. 9 - Prob. 5RECh. 9 - Prob. 6RECh. 9 - Prob. 7RECh. 9 - Prob. 8RECh. 9 - Prob. 9RECh. 9 - Prob. 10RECh. 9 - Prob. 11RECh. 9 - Prob. 12RECh. 9 - Prob. 13RECh. 9 - Prob. 14RECh. 9 - Prob. 15RECh. 9 - Prob. 16RECh. 9 - Prob. 1PECh. 9 - Prob. 2PECh. 9 - Prob. 3PECh. 9 - Prob. 4PECh. 9 - Prob. 7PECh. 9 - Prob. 8PECh. 9 - Prob. 9PECh. 9 - Prob. 10PECh. 9 - Prob. 11PECh. 9 - Prob. 12PECh. 9 - Prob. 13PECh. 9 - Prob. 14PECh. 9 - Prob. 15PECh. 9 - Prob. 16PECh. 9 - Prob. 18PECh. 9 - Prob. 19PECh. 9 - Prob. 20PECh. 9 - Prob. 21PECh. 9 - Prob. 22PECh. 9 - Prob. 23PECh. 9 - Prob. 1PPCh. 9 - Prob. 2PPCh. 9 - Prob. 3PPCh. 9 - Prob. 4PPCh. 9 - Prob. 5PPCh. 9 - Prob. 6PPCh. 9 - Prob. 7PPCh. 9 - Prob. 8PPCh. 9 - Prob. 9PPCh. 9 - Prob. 10PPCh. 9 - Prob. 11PPCh. 9 - Prob. 12PPCh. 9 - Prob. 13PPCh. 9 - Prob. 14PPCh. 9 - Prob. 15PPCh. 9 - Prob. 16PPCh. 9 - Prob. 17PPCh. 9 - Prob. 18PPCh. 9 - Prob. 19PPCh. 9 - Prob. 20PPCh. 9 - Prob. 21PPCh. 9 - Prob. 22PPCh. 9 - Prob. 23PP
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