A big olive ( m = 0.50 kg) lies at the origin of an xy coordinate system, and a big Brazil nut ( M = 1.5 kg) lies at the point (1.0, 2.0) m. At t = 0, a force F → o = (2.0 i ^ + 3.0 j ^ ) N begins to act on the olive, and a force F → n = (−3.0 i ^ − 2.0 j ^ ) N begins to act on the nut. In unit-vector notation, what is the displacement of the center of mass of the olive-nut system at t = 4.0 s, with respect to its position at t = 0?
A big olive ( m = 0.50 kg) lies at the origin of an xy coordinate system, and a big Brazil nut ( M = 1.5 kg) lies at the point (1.0, 2.0) m. At t = 0, a force F → o = (2.0 i ^ + 3.0 j ^ ) N begins to act on the olive, and a force F → n = (−3.0 i ^ − 2.0 j ^ ) N begins to act on the nut. In unit-vector notation, what is the displacement of the center of mass of the olive-nut system at t = 4.0 s, with respect to its position at t = 0?
A big olive (m = 0.50 kg) lies at the origin of an xy coordinate system, and a big Brazil nut (M = 1.5 kg) lies at the point (1.0, 2.0) m. At t = 0, a force
F
→
o
= (2.0
i
^
+ 3.0
j
^
) N begins to act on the olive, and a force
F
→
n
= (−3.0
i
^
− 2.0
j
^
) N begins to act on the nut. In unit-vector notation, what is the displacement of the center of mass of the olive-nut system at t = 4.0 s, with respect to its position at t = 0?
You're on an interplanetary mission, in an orbit around the Sun. Suppose you make a maneuver that brings your perihelion in closer to the Sun but leaves your aphelion unchanged. Then you must have
Question 2 options:
sped up at perihelion
sped up at aphelion
slowed down at perihelion
slowed down at aphelion
The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!
The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE DO NOT USE LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!
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