EBK BIOLOGY
5th Edition
ISBN: 9780133996807
Author: Maier
Publisher: PEARSON CUSTOM PUB.(CONSIGNMENT)
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Question
Chapter 9, Problem 11LTB
Summary Introduction
To analyze:
Whether the statement ' the kidney cell and the heart cell of a cat contain same genes' is true or false.
Introduction:
The genes are unit of hereditary in the organisms. All the characteristics leading to the functioning of the body is influenced by the genes. In the eukaryotic cells, the genes are present in the nucleus.
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In humans, hemophilia is a sex-linked trait. Females can be normal, carriers, or have the disease. Males will either have the disease or not (but they won’t ever be carriers).
X H X H = female, non-hemophilic
X H X h = female, carrier
X h X h = female, hemophilia
X H Y = male, non-hemophilic
X h Y= male, hemophiliac
a.) Show the cross of a man who has hemophilia with a woman who is a carrier. What is the probability that their children will have the disease?
b.) A woman who is a carrier marries a non-hemophilic man. Show the cross. What is the probability that their children will have hemophilia? What sex will a child in the family with hemophilia be?
c.) A woman who has hemophilia marries a non-hemophilic man. How many of their children will have hemophilia, and what is their sex?
A man with group A blood marries a woman with group B blood. Their child has group O blood. What is the genotype of the man? show your solution
Please help
True or false, if false rewrite the statement in a way that makes it true.
a) A cell spends most of its life dividing rather than carrying out typical cell functions.
False
b) We can know the genotype of an individual simply by looking at their phenotype.
False
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- Use the following information to answer the next question. In humans, the allele for normal blood clotting, H, is dominant to the allele for hemophilia, h. The trait is X-linked. A woman who is not a hemophiliac has a father who is a hemophiliac. If this woman has a child with a man who is a hemophiliac, what is the probability of them having a hemophiliac son? (Record your answer as a frequency between 0 and 1 rounded to two decimal places. Include the decimal.) Answer: Answerarrow_forwardHemophilia is inherited as a sex-linked recessive trait. A non-hemophilic man marries a non-hemophilic woman whose father had hemophilia. With respect to this information, indicate all possible genotypes their children could possibly have. Show ALL work using punnett squares.arrow_forwardIn 1967, a couple accused a hospital of switching their baby with another. DNA interpretation did not exist at this time so the hospital traced the blood types of the family in order to determine if a mistake was made. The mother had Type A blood, the father had Type AB blood, and the baby had Type O blood. Use the Punnett square to defend your answer to the following question: Did the hospital make a mistake and switch the baby? ____________arrow_forward
- Hemophilia is an X-linked disorder that affects the body’s ability to create blood clots. The allele for normal blood clotting, XH, is dominant over the allele for hemophilia, Xh. An unaffected daughter from the above cross married a man who does not have hemophilia. Determine the probability of their offspring being A daughter with hemophilia A daughter without hemophilia A son with hemophilia A son without hemophilia Express your answer as a phenotypic ratio. Number: Answer Answer Answer Answer Phenotype: Affected female Unaffected female Affected male Unaffected malearrow_forwardA gene is composed of two alleles. An allele can be either dominant or recessive. Suppose that a husband and wife, who are both carriers of the sickle-cell anemia allele but do not have the disease, decide to have a child. Because both parents are carriers of the disease, each has one dominant normal-cell allele (S) and one recessive sickle-cell allele (s). Therefore, the genotype of each parent is Ss. Each parent contributes one allele to his or her offspring with each allele being equally likely. Complete parts a) through c) below. a) Genes are always written with the dominant gene first. Therefore, there are two instances the offspring could have genotype Ss (one if the mother contributes the dominant allele and the father contributes the non-dominant allele; and one if the father contributes the dominant allele and the mother contributes the non-dominant allele). List the other two possible genotypes of the offspring. (Use a comma to separate answers as needed.)arrow_forwardThe allele for color-blindness is carried on the X chromosome. Making color blindness (a recessive trait) an X - linked trait. A colorblind make and a carrier female for color blindness. (But is not colorblind herself) have a child. Show your work! A) what is the % chance that their son will be color blind? B) what is the % chance that their daughter will be color blind?arrow_forward
- Jill has a son named Jack. She claims that James is the father. James denies this. Jill has Type A blood. Jack has Type O blood. James has Type B blood. Based on this information, what would a court decide on this problem? Question 3 options: James could be the father of Jack because James could be heterozygous James is not the father of Jack because their phenotypes are different James is not the father of Jack because their genotypes are different James could be the father of Jack because type B blood is usually I^Bi James is the father of Jack because he passed on a recessive allelearrow_forwardHemophilia is a blood disorder which is sex-linked. A woman carrier has children with a normal man. Determine the chances for girls and boys with hemophilia. [Remember that females have the XX genotype and males have the XY genotype. Do not place an allele on the Y chromosome. Example: XN Xn for female; Xn Y for male]arrow_forwardConsider the selfed offspring of a AaBbCcDd individual: What is the probability that offspring will have the following genotypes: AABBCCDD AaBbCCDd ● • A_B_C_D_ BbCCDd ● ● ● ● ● 1/4 x 1/4 x 1/4 x 1/4= 1/256 1/2 x 1/2 x 1/4 x 1/2= 1/32 3/4 x 3/4 x 3/4 x 3/4= 81/256 1 x 1/2 x 1/4 x 1/2= 1/16 Same genotype as the parent? A.1 B. 1/1/12 C. D.1/8 E.1/16arrow_forward
- In Drosophila, the gene for red and white eye colour is found on the X chromosome. The allele for red eyes (XR) is dominant to the allele for white eyes (Xr). A heterozygous red-eyed female fruit fly was crossed with a white-eyed male fruit fly. Complete the following Punnett square for this cross. Answer Answer Answer Answer Answer Y Answer Answerarrow_forwardExplain how twins could have the same genetic material but not look exactly the same or have the same chances of suffering from diseases such as cancer. A BIUS #arrow_forwardWhich of the options below is not an example of Pleiotropy? Tay-Sachs Disease phenylketonuria Marfan syndromearrow_forward
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