
Concept explainers
(a)
To explain in what way is the point unusual and does it have high leverage, a large residual or both and do you think that point is an influential point and if that point were removed would the
(a)

Answer to Problem 11E
It does not have influential point and correlation would increase and slope does not change much.
Explanation of Solution
Each of the four scatterplots given in the question that follow shows a cluster of points and one stray point. Now, by looking at the (a) scatterplot, we can say that it has a high leverage and it is of small residual. And it does not have an influential point or not influential for the slope. Now, if that point were removed than correlation would decrease because outlier has large
(b)
To explain in what way is the point unusual and does it have high leverage, a large residual or both and do you think that point is an influential point and if that point were removed would the correlation become stronger or weaker and also if that point were removed would the slope of the regression line increase or decrease, for the scatterplot (b) given in the question.
(b)

Answer to Problem 11E
It does have an influential point and correlation would weaken and slope will move toward zero.
Explanation of Solution
Each of the four scatterplots given in the question that follow shows a cluster of points and one stray point. Now, by looking at the (b) scatterplot, we can say that it has a high leverage and small residual. Moreover, it has an influential point. And if that point were removed than the correlation would weaken and will increase towards zero. And also if that point were removed than the slope would increase towards zero since outlier makes it negative.
(c)
To explain in what way is the point unusual and does it have high leverage, a large residual or both and do you think that point is an influential point and if that point were removed would the correlation become stronger or weaker and also if that point were removed would the slope of the regression line increase or decrease, for the scatterplot (c) given in the question.
(c)

Answer to Problem 11E
It does have influential point and correlation would increase and slope would increase slightly.
Explanation of Solution
Each of the four scatterplots given in the question that follow shows a cluster of points and one stray point. Now, by looking at the (c) scatterplot, we can say that it has some leverage and large residual. Also, yes, it has an influential point. And if that point were removed than correlation would increase since scatter would decrease. And also if that point were removed than slope would increase slightly since the scatter would decrease.
(d)
To explain in what way is the point unusual and does it have high leverage, a large residual or both and do you think that point is an influential point and if that point were removed would the correlation become stronger or weaker and also if that point were removed would the slope of the regression line increase or decrease, for the scatterplot (d) given in the question.
(d)

Answer to Problem 11E
It does not have influential point and correlation would become stronger and slope would change very little.
Explanation of Solution
Each of the four scatterplots given in the question that follow shows a cluster of points and one stray point. Now, by looking at the (d) scatterplot, we can say that it has little leverage and large residual. And no, it does not have an influential point. And if that point were removed than correlation would increase since scatter would decrease and in this case the slope would change very little as scatter would decrease.
Chapter 9 Solutions
Stats: Modeling the World Nasta Edition Grades 9-12
Additional Math Textbook Solutions
Thinking Mathematically (6th Edition)
Elementary Statistics: Picturing the World (7th Edition)
Precalculus
Elementary Statistics
University Calculus: Early Transcendentals (4th Edition)
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
- The average miles per gallon for a sample of 40 cars of model SX last year was 32.1, with a population standard deviation of 3.8. A sample of 40 cars from this year’s model SX has an average of 35.2 mpg, with a population standard deviation of 5.4. Find a 99 percent confidence interval for the difference in average mpg for this car brand (this year’s model minus last year’s).Find a 99 percent confidence interval for the difference in average mpg for last year’s model minus this year’s. What does the negative difference mean?arrow_forwardA special interest group reports a tiny margin of error (plus or minus 0.04 percent) for its online survey based on 50,000 responses. Is the margin of error legitimate? (Assume that the group’s math is correct.)arrow_forwardSuppose that 73 percent of a sample of 1,000 U.S. college students drive a used car as opposed to a new car or no car at all. Find an 80 percent confidence interval for the percentage of all U.S. college students who drive a used car.What sample size would cut this margin of error in half?arrow_forward
- You want to compare the average number of tines on the antlers of male deer in two nearby metro parks. A sample of 30 deer from the first park shows an average of 5 tines with a population standard deviation of 3. A sample of 35 deer from the second park shows an average of 6 tines with a population standard deviation of 3.2. Find a 95 percent confidence interval for the difference in average number of tines for all male deer in the two metro parks (second park minus first park).Do the parks’ deer populations differ in average size of deer antlers?arrow_forwardSuppose that you want to increase the confidence level of a particular confidence interval from 80 percent to 95 percent without changing the width of the confidence interval. Can you do it?arrow_forwardA random sample of 1,117 U.S. college students finds that 729 go home at least once each term. Find a 98 percent confidence interval for the proportion of all U.S. college students who go home at least once each term.arrow_forward
- Suppose that you make two confidence intervals with the same data set — one with a 95 percent confidence level and the other with a 99.7 percent confidence level. Which interval is wider?Is a wide confidence interval a good thing?arrow_forwardIs it true that a 95 percent confidence interval means you’re 95 percent confident that the sample statistic is in the interval?arrow_forwardTines can range from 2 to upwards of 50 or more on a male deer. You want to estimate the average number of tines on the antlers of male deer in a nearby metro park. A sample of 30 deer has an average of 5 tines, with a population standard deviation of 3. Find a 95 percent confidence interval for the average number of tines for all male deer in this metro park.Find a 98 percent confidence interval for the average number of tines for all male deer in this metro park.arrow_forward
- Based on a sample of 100 participants, the average weight loss the first month under a new (competing) weight-loss plan is 11.4 pounds with a population standard deviation of 5.1 pounds. The average weight loss for the first month for 100 people on the old (standard) weight-loss plan is 12.8 pounds, with population standard deviation of 4.8 pounds. Find a 90 percent confidence interval for the difference in weight loss for the two plans( old minus new) Whats the margin of error for your calculated confidence interval?arrow_forwardA 95 percent confidence interval for the average miles per gallon for all cars of a certain type is 32.1, plus or minus 1.8. The interval is based on a sample of 40 randomly selected cars. What units represent the margin of error?Suppose that you want to decrease the margin of error, but you want to keep 95 percent confidence. What should you do?arrow_forward3. (i) Below is the R code for performing a X2 test on a 2×3 matrix of categorical variables called TestMatrix: chisq.test(Test Matrix) (a) Assuming we have a significant result for this procedure, provide the R code (including any required packages) for an appropriate post hoc test. (b) If we were to apply this technique to a 2 × 2 case, how would we adapt the code in order to perform the correct test? (ii) What procedure can we use if we want to test for association when we have ordinal variables? What code do we use in R to do this? What package does this command belong to? (iii) The following code contains the initial steps for a scenario where we are looking to investigate the relationship between age and whether someone owns a car by using frequencies. There are two issues with the code - please state these. Row3<-c(75,15) Row4<-c(50,-10) MortgageMatrix<-matrix(c(Row1, Row4), byrow=T, nrow=2, MortgageMatrix dimnames=list(c("Yes", "No"), c("40 or older","<40")))…arrow_forward
- MATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th...StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C...StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. WallnauPublisher:Cengage Learning
- Elementary Statistics: Picturing the World (7th E...StatisticsISBN:9780134683416Author:Ron Larson, Betsy FarberPublisher:PEARSONThe Basic Practice of StatisticsStatisticsISBN:9781319042578Author:David S. Moore, William I. Notz, Michael A. FlignerPublisher:W. H. FreemanIntroduction to the Practice of StatisticsStatisticsISBN:9781319013387Author:David S. Moore, George P. McCabe, Bruce A. CraigPublisher:W. H. Freeman





