Explanation Given that the difference in mercury level is 25 cm , and the density of air at the plane’s altitude is 0.90 kg/m 3 . Write the Bernoulli’s equation for an ideal fluid flow. P 1 + ρ a g y 1 + 1 2 ρ a v 1 2 = P 2 + ρ a g y 2 + 1 2 ρ a v 2 2 (I) Here, P is the pressure, ρ a is the density of the fluid (air), v is the speed of the fluid, y 1 is the altitude, and g is the acceleration due to gravity. = For y 1 ≈ y 2 , and v 2 = 0 (for the opening, where the air speed is zero), the equation (I) can be simplified as, P 1 + 1 2 ρ a v 1 2 = P 2 P 2 − P 1 = 1 2 ρ a v 1 2 Δ P = 1 2 ρ a v 1 2 (II) Here, Δ P is the pressure difference. Write the expression for pressure difference in terms of mercury in the device. Δ P = ρ m g Δ y m (III) Here, ρ m is the density of mercury, Δ y m is the difference in mercury level

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Chapter 9, Problem 106P

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The airspeed of the plane.

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Chapter 9, Problem 104P

Chapter 9, Problem 107P

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