Explanation Given Information: A rectangle with width fixed at 8 ft. Formula used: The perimeter of rectangle is equal to 2 ( l + w ) . where l is length and w is width. Calculation: 1. Familiarize: Suppose the length of the rectangle is 80 feet which make the perimeter at least 200 ft. 2 ( 80 + 8 ) = 160 + 16 = 176 This shows that the length of the rectangle is not 80 feet because the perimeter is less than 200 feet. It means guess the length of the rectangle is 80 feet is incorrect. 2. Translate: Let x be the length of a rectangle. Reword: The perimeter is at least 200 ft. Translate: 2 ( l + 8 ) ≥ 200 . 3. Solve: Solve 2 ( l + 8 ) ≥ 200 . 2 ( l + 8 ) ≥ 200 l + 8 ≥ 200 2 l + 8 ≥ 100 l ≥ 100 − 8 And l ≥ 92 4. Check: Check by substituting l = 92 in 2 ( l + 8 ) . 2 ( 92 + 8 ) = 2 ( 100 ) = 200 Hence, the perimeter at least 200 ft when its length is 92 feet or more

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ISBN: 9781323235911

Author: BITTINGER

Publisher: Pearson Custom Publishing

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Chapter 8.8, Problem 37ES

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To calculate: The lengths of a rectangle that will make the perimeter at least 200ft and at most 200ft if rectangle with width fixed at 8 ft.

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Chapter 8.8, Problem 36ES

Chapter 8.8, Problem 38ES

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The lengths of a rectangle that will make the perimeter at least 200ft and at most 200ft if rectangle with width fixed at 8 ft.

Solution Summary: The author calculates the perimeter of a rectangle with width fixed at 8 ft. The length of the rectangle is 92 feet or more.

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To calculate: The lengths of a rectangle that will make the perimeter at least 200ft and at most 200ft if rectangle with width fixed at 8 ft.

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