The product obtained for given hydroboration-oxidation has to be drawn. Concept Introduction: Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition. Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

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Answer 1

Question

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

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eks.com/aleksogi/x/sl.exe/1o_u-IgNslkr7j8P3jH-IQs_pBanHhvTCeeBZbufuBYTI0Hz7m7D3ZS17Hd6m-HIl6n52njJN-TXdQA2X9yID-1SWQJTgnjARg30 111 States of Matter Understanding conceptual components of the enthalpy of solution 0/5 Ge A small amount of acetonitrile (CH, CN) is dissolved in a large amount of water. Imagine separating this process into the four stages sketched below. (These sketches show only a portion of the substances, so you can see the density and distribution of atoms and molecules in them.) CH,CN H₂O B 88 C Use these sketches to answer the questions in the table below. The enthalpy of solution AH is negative soln when CH3CN dissolves in water. Use this information to list the stages in order of increasing enthalpy. Would heat be absorbed or released if the system moved from Stage C to D? What force would oppose or favor the system moving from Stage C to D? Check all that apply. 1 absorbed O released neither absorbed nor released. none O ionic bonding force covalent bonding force…

In a system with an anodic overpotential, the variation of ŋ as a function of the current density: 1. at low fields is linear 2. at higher fields, it follows Tafel's law Find the range of current densities for which the overpotential has the same value as when calculated for cases 1 and 2 (maximum relative difference of 5% with respect to the behavior for higher fields). To which overpotential range does this correspond? Data: 10 = 1.5 mA cm², T = 300°C, ẞ = 0.64, R = 8.314 J K 1 mol‍¹ and F = 96485 C mol-1.

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Answer 2

Question

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

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Answer 3

Question

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

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Answer 4

Question

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Expert Solution & Answer

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Answer 5

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 6

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 7

Chapter 8.7, Problem 14CC

(a)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 10

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 11

(c)

Interpretation Introduction

Interpretation:

The product obtained for given hydroboration-oxidation has to be drawn.

Concept Introduction:

Hydroboration-oxidation reaction: Addition of –H and –OH group across the double bond in presence of borane and hydrogen peroxide with base is known as hydroboration-oxidation reaction. It follows Anti-Markovnikov’s addition.

Anti-Markovnikov’s rule: An unsymmetrical alkene reacts with hydrogen halide in which halide ions goes to the less substitution position of carbon-carbon double bond which provides alkyl halides.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 8.4 - Prob. 1CC Ch. 8.4 - Prob. 2CC Ch. 8.4 - Draw a mechanism for the following...Ch. 8.4 - Prob. 3PTS Ch. 8.4 - Prob. 4ATS Ch. 8.4 - Prob. 5CC Ch. 8.4 - Prob. 2LTS Ch. 8.4 - Prob. 6PTS Ch. 8.5 - Prob. 8CC Ch. 8.5 - Prob. 9CC

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