The number of possible two-person relationships from a group of 3 people, with the size of the group complexity of interpersonal relationship increasing.
The number of possible two-person relationships from a group of 3 people, with the size of the group complexity of interpersonal relationship increasing.
Solution Summary: The author calculates the number of possible two-person relationships from a group of 3 people, with the size of the group complexity of interpersonal relationship increasing.
To calculate: The number of possible two-person relationships from a group of 3 people, with the size of the group complexity of interpersonal relationship increasing.
(b)
To determine
To calculate: The number of possible two-person relationships from a group of 8 people, with the size of the group complexity of interpersonal relationship increasing.
(c)
To determine
To calculate: The number of possible two-person relationships from a group of 12 people, with the size of the group complexity of interpersonal relationship increasing.
(d)
To determine
To calculate: The number of possible two-person relationships from a group of 20 people, with the size of the group complexity of interpersonal relationship increasing.
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Solve the linear system of equations attached using Gaussian elimination (not Gauss-Jordan) and back subsitution.
Remember that:
A matrix is in row echelon form if
Any row that consists only of zeros is at the bottom of the matrix.
The first non-zero entry in each other row is 1. This entry is called aleading 1.
The leading 1 of each row, after the first row, lies to the right of the leading 1 of the previous row.
PRIMERA EVALUACIÓN SUMATIVA
10. Determina la medida de los ángulos in-
teriores coloreados en cada poligono.
⚫ Octágono regular
A
11. Calcula es número de lados qu
poligono regular, si la medida
quiera de sus ángulos internos
• a=156°
A= (-2x+80
2
156 180-
360
0 = 24-360
360=24°
• a = 162°
1620-180-360
6=18-360
360=19
2=360=
18
12. Calcula las medida
ternos del cuadrilá
B
X+5
x+10
A
X+X+
Sx+6
5x=3
x=30
0
лаб
• Cuadrilátero
120°
110°
• α = 166° 40'
200=180-360
0 =
26-360
360=20
ひ=360
20
18 J
60°
⚫a=169° 42' 51.43"
169.4143180-340
0 = 10.29 54-360
360 10.2857
2=360
10.2857
@Sa
Chapter 8 Solutions
Bundle: College Algebra, Loose-leaf Version, 10th + WebAssign Printed Access Card for Larson's College Algebra, 10th Edition, Single-Term
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