Explanation Given Information: The provided equation is 2 x − 3 y = 12 . Graph: Consider the equation, 2 x − 3 y = 12 . Recall that to calculate y -intercept, replace x with 0 and solve for y. Substitute 0 for x in 2 x − 3 y = 12 . 2 ( 0 ) − 3 y = 12 − 3 y = 12 Solve for y . Divide both sides by − 3 . − 3 y − 3 = 12 − 3 y = − 4 Thus, y -intercept is ( 0 , − 4 ) . Recall that to calculate x -intercept, replace y with 0 and solve for x. Substitute 0 for y in 2 x − 3 y = 12 . 2 x − 3 ( 0 ) = 12 2 x = 12 Solve for x . Divide both sides by 2 . 2 x 2 = 12 2 x = 6 Thus, x -intercept is ( 6 , 0 ) . Consider the equation, 2 x − 3 y = 12 . Subtract 2 x from both sides. 2 x − 3 y − 2 x = 12 − 2 x − 3 y = 12 − 2 x Solve for y . Divide both sides by − 3 . − 3 y − 3 = 12 − 2 x − 3 y = − 4 + 2 3 x y = 2 3 x − 4 Calculate the value of the equation y for different values of x . Substitute 0 for x in y = 2 3 x − 4 . y = 2 3 x − 4 = 2 3 ( 0 ) − 4 = 0 − 4 = − 4 Thus, y = − 4 . Substitute 3 for x in y = 2 3 x − 4 . y = 2 3 x − 4 = 2 3 ( 3 ) − 4 = 2 − 4 = − 2 Thus, y = − 2

Elementary Algebra: Concepts and Applications (10th Edition)

10th Edition

ISBN: 9780134441375

Author: Marvin L. Bittinger, David J. Ellenbogen, Barbara L. Johnson

Publisher: PEARSON

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Chapter 8.5, Problem 54ES

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Chapter 8.5, Problem 53ES

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Chapter 8 Solutions

Elementary Algebra: Concepts and Applications (10th Edition)

Ch. 8.1 - Find the square roots of 81.Ch. 8.1 - Prob. 2YT Ch. 8.1 - Prob. 3YT Ch. 8.1 - Prob. 4YT Ch. 8.1 - Prob. 5YT Ch. 8.1 - Prob. 6YT Ch. 8.1 - Prob. 7YT Ch. 8.1 - Prob. 8YT Ch. 8.1 - Prob. 1CYU Ch. 8.1 - Prob. 2CYU

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To graph: The equation defined as 2 x − 3 y = 12 .

Solution Summary: The author analyzes the equation, 2x-3y=12, and calculates y -intercept and solves for x.

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