Explanation Given Information: The provided integral is ∫ 1 2 ∫ 2 3 ( 1 x + 1 y ) d x d y . Formula used: The double integral over a rectangle, if R is the rectangle a ≤ x ≤ b and c ≤ y ≤ d , then ∫ ∫ f ( x , y ) d x d y = ∫ c d ( ∫ a b f ( x , y ) d x ) d y = ∫ a b ( ∫ c d f ( x , y ) d y ) d x Calculation: Consider the integral, ∫ 1 2 ∫ 2 3 ( 1 x + 1 y ) d x d y . Integrate the above integral from inside out, ∫ 1 2 ∫ 2 3 ( 1 x + 1 y ) d x d y = ∫ 1 2 ( ∫ 2 3 ( 1 x + 1 y ) d x ) d y . Integrate the integral ∫ 1 2 ( ∫ 2 3 ( 1 x + 1 y ) d x ) d y with respect to x

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ISBN: 9781337514309

Author: Waner

Publisher: Cengage

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Chapter 8.5, Problem 4E

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To calculate: The value of the integral ∫12∫23(1x+1y)dxdy.

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Chapter 8.5, Problem 3E

Chapter 8.5, Problem 5E

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Chapter 8 Solutions

Applied Calculus

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The value of the integral ∫ 1 2 ∫ 2 3 ( 1 x + 1 y ) d x d y .

Solution Summary: The author explains how to calculate the value of the integral, if R is the rectangle ale x

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To calculate: The value of the integral ∫12∫23(1x+1y)dxdy.

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Chapter 8 Solutions