Explanation Given: The encoded matrix is, A = [ 1 2 2 3 7 9 − 1 − 4 − 7 ] The message is, LANDING SUCCESSFUL Approach: To convert the coded message into uncoded row matrices with n entries, convert the message into numbers and partition the number, The number that represents each letter is the place it comes in the alphabetical sequence starting from A as number 1 to Z as number 26. 0 is use for the blank space. To encode a message, multiply each uncoded row matrices with the encoded matrix. Calculation: Partition of the message into the group of three produces the uncoded row matrices, [ 12 1 14 ] [ 4 9 14 ] [ 7 0 19 ] [ 21 3 3 ] [ 5 19 19 ] [ 6 21 12 ] Multiply the matrix uncoded row matrix [ 12 1 14 ] with encoded matrix A . [ 12 1 14 ] [ 1 2 2 3 7 9 − 1 − 4 − 7 ] = [ 1 − 25 − 65 ] Multiply the matrix uncoded row matrix [ 4 9 14 ] with encoded matrix A . [ 4 9 14 ] [ 1 2 2 3 7 9 − 1 − 4 − 7 ] = [ 17 15 − 9 ] Multiply the matrix uncoded row matrix [ 7 0 19 ] with encoded matrix A . [ 7 0 19 ] [ 1 2 2 3 7 9 − 1 − 4 − 7 ] = [ − 12 − 62 − 119 ] Multiply the matrix uncoded row matrix [ 21 3 3 ] with encoded matrix A

Bundle: Precalculus, Loose-leaf Version, 10th + WebAssign Printed Access Card for Larson's Precalculus, 10th Edition, Single-Term

10th Edition

ISBN: 9781337605090

Author: Ron Larson

Publisher: Cengage Learning

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Chapter 8.5, Problem 49E

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The cryptogram for the message LANDING SUCCESSFUL using the matrix A=[122379−1−4−7].

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Chapter 8.5, Problem 48E

Chapter 8.5, Problem 50E

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Bundle: Precalculus, Loose-leaf Version, 10th + WebAssign Printed Access Card for Larson's Precalculus, 10th Edition, Single-Term

Ch. 8.1 - Prob. 1CP Ch. 8.1 - Prob. 2CP Ch. 8.1 - Prob. 3CP Ch. 8.1 - Prob. 4CP Ch. 8.1 - Prob. 5CP Ch. 8.1 - Prob. 6CP Ch. 8.1 - Prob. 7CP Ch. 8.1 - Prob. 8CP Ch. 8.1 - Prob. 9CP Ch. 8.1 - Prob. 1E

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The cryptogram for the message LANDING SUCCESSFUL using the matrix A = [ 1 2 2 3 7 9 − 1 − 4 − 7 ] .

Solution Summary: The author explains how to determine the cryptogram for the message LANDING SUCCESSFUL using the matrix A=left.

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The cryptogram for the message LANDING SUCCESSFUL using the matrix A=[122379−1−4−7].

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Chapter 8 Solutions