OWLv2 with LabSkills for Gilbert/Martin's Experimental Organic Chemistry: A Miniscale & Microscale Approach, 6th Edition, [Instant Access], 4 terms (24 months)
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Chapter 8.5, Problem 3E

(a)

Interpretation Introduction

Interpretation: The fragments responsible for the given m/z values needs to be determined.

Concept Introduction: A mass spectrum is formed between intensity and m/z ratio which represents a chemical analysis. For a sample, mass spectrum is a pattern that represents the distribution of ion by mass in sample. Here, m/z ratio is mass to charge ratio of the sample.

(b)

Interpretation Introduction

Interpretation: The reason for very low density of the peak at 113 needs to be explained.

Concept Introduction: A mass spectrum is formed between intensity and m/z ratio which represents a chemical analysis. For a sample, mass spectrum is a pattern that represents the distribution of ion by mass in sample. Here, m/z ratio is mass to charge ratio of the sample.

(c)

Interpretation Introduction

Interpretation: The value of m/z needs to be calculated for the parent peak and reason for it to not observed needs to be explained.

Concept Introduction: A mass spectrum is formed between intensity and m/z ratio which represents a chemical analysis. For a sample, mass spectrum is a pattern that represents the distribution of ion by mass in sample. Here, m/z ratio is mass to charge ratio of the sample.

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Which compound correlates to the following mass spectrum? 100 80 20 50 75 100 125 150 m/z Relative htensity
Q.1. Predict the relative intensity of the M, M+1, and M+2 peaks for a low resolution mass spectrum of a compound with molecular formula, C6H13Br. The natural abundances of the select isotopes are given below. 35 Cl: 75.8% 79Br: 50.5% 12C: 98.89% 37Cl: 24.2% (The ratio is almost 3:1) 81Br: 49.5% (The ratio is almost 1:1) 13C: 1.11%
Mass spectroscopic.  What is the isotopic peak pattern of each : Organic compound with 2 bromine atoms. Organic compound with 2 chlorine atoms.
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