Explanation Given: The differential equation is 2 x 2 y ″ ( x ) + 13 x y ′ ( x ) + 15 y ( x ) = 0 Approach: A second-order homogeneous equation in the form a x 2 y ″ ( x ) + b x y ′ ( x ) + c y ( x ) = 0 is called Cauchy - Euler equation, where a ≠ 0 and b and c are real numbers. If the equation has a singular point then it has solution in the form of y = x r . If the roots of equation a r 2 + b r + c = 0 are real such that r = r 1 = r 2 , then general solution is y ( t ) = c 1 e r t + c 2 t e r t If the roots of equation a r 2 + b r + c = 0 are real such that r 1 ≠ r 2 then general solution is y ( t ) = c 1 e r 1 t + c 2 e r 2 t If the roots of equation a r 2 + b r + c = 0 are imaginary in form of r 1 , 2 = α ± β i then general solution is y ( t ) = e a t ( c 1 cos β t + c 2 sin β t ) Calculation: Consider the given problem. 2 x 2 y ″ ( x ) + 13 x y ′ ( x ) + 15 y ( x ) = 0 ... ( 1 ) Let, w ( r , x ) = x r and L is the left hand side of the equation. Differentiate w ( r , x ) = x r upto second derivative.

Fundamentals of Differential Equations [With CDROM] - 7th Edition

7th Edition

ISBN: 9780321410481

Author: Saff, Edward B., Snider, Arthur David, Nagle, R. Kent

Publisher: Addison Wesley

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The general solution of a differential equation by substitution of y = x r where x > 0 .

Solution Summary: The author explains the general solution of a differential equation by substitution of y=xr.

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The general solution of a differential equation by substitution of y = x r where x > 0 .

To find:

The general solution of a differential equation by substitution of y=xr where x>0.