Vector Mechanics for Engineers: Statics
12th Edition
ISBN: 9781259977268
Author: Ferdinand P. Beer, E. Russell Johnston Jr., David Mazurek
Publisher: McGraw-Hill Education
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Chapter 8.4, Problem 8.120P
(a)
To determine
Find the smallest weight W for which the equilibrium is maintained.
(b)
To determine
Find the largest weight W that can be raised for the given condition.
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Students have asked these similar questions
Bolted Joint Design
Bolted Frames
Total Force due to door weight: P =
240
lb
Number of Bolts: N =
Distance to Bolt C/L: a =
4
N/A
Bolt Material -
Allowable shear stress of bolt material: T₂ =
x Distance from Bolt centroid to bolt: x =
y Distance from Bolt centroid to bolt: y =
Degrees per Radian-
Results
y-Load on each bolt: F, =
Moment resisted by bolt pattern: M =
Radial distance from Bolt centroid to bolt: r =
Sum squares of all radial distances: Σr²
Force on each bolt to resist moment: F, -
Angle for force composition: e=
X-Force on each bolt to resist moment: F-
y-Force on each bolt to resist moment: Fly
Total y-Force on each bolt: Fy =
Resultant force on bolt 1: R₁ =
Required shear stress area for a bolt: A₂ =
ASTM Grade
A307 Steel
10,000
0
psi
from Table 20-1
3.0
57.296
in
degrees
lb per bolt
lb-in
Formula
FS-P/N
M-Px XB
r = (x² + y²)0.5
in²
Σ
4r²
Mr
F₁ =
Στ
lb
degrees
lb
lb
lb
Minimum Bolt Diameter: Din =
Rounded up Bolt Diameter: D =
55
P.
1.5 in
2 in (3x)
1 in
This bracket…
University of Babylon
Collage of Engineering/
Al-Musayab
Department of Automobiles
Final Examination/ Stage: 3rd
Notes:
Answer 4 questions only
2023-2202
Subject: Theory of vehicles
Date: 2023\06\10-Saturday
Time: Three Hours
Course 2nd Attempt 1st
Q1: A Hooke's coupling connects two shafts whose axes are inclined at 30°. The
of the driven shaft? Find the maximum value of retardation or acceleration and
driving shaft rotates uniformly at 600 rpm. What are the extreme angular velocities
state the angle where both will occur.
(12.5 Marks)
Q2: Four masses, A, B, C, and D), revolve at equal radii and are equally spaced
along a shaft. The mass B is 7 kg, and the radius of C and D make angles of 90°
and 240°, respectively, with the radius of B. Find the magnitude of the masses A,
C, and D and the angular position of A so that the system may be completely
balanced.
(12.5 Marks)
Q3: A cam has straight worked faces that are tangential to a base circle of diameter
90 mm. The follower is a roller…
Problem 18-26
Added
Extension Springs
Spring Material
ASTM A227
Modulus of Elasticity of the Material in Shear: G 1.150E+07 psi
Average Service
Max Operating Load: F₁ =
100
lb
Max Length between attachment points: L₁ =
60.00 in
20.00 lb
26.00
1.400
Min Operating Load: F₁ =
Min Length between attachment points: L₁ =
Maximum Outside Diameter =
in
in
Results
Note: you select a wire diameter from the "US steel wire gage"
column in table 18-2
Formula
k =
AF/AL
k = (F0-F1)/(Lo - L₁)
Spring Rate: k =
lb/in
Assumed Trial Outside Diameter: OD =
Assumed Trial Mean: D ma
Assumed Design Stress in Spring: Tda
in
1.070
in
102,000 psi
Assumed Wahl Factor: K =
1.2
Calculated Wire Diameter: Dwa
Actual Wire Diameter: Dw
Actual outer diameter: OD =
Actual inner diameter: ID=
Spring Index: C =
See Figure 18-8
Dw=
[8KF Dm
πTd
1/3
in
5' 5' 5' 5'
This corresponds to US Steel 9 wire gage
ID = Dm - Dw
C = Dm/Dw
4C - 1
0.615
K =
+
4C
-
с
Wahl Factor: K =
8KFDm
8KFC
T =
TD
πD
Stress in Spring at F = Fo: To
psi…
Chapter 8 Solutions
Vector Mechanics for Engineers: Statics
Ch. 8.1 - Knowing that the coefficient of friction between...Ch. 8.1 - Two blocks A and B are connected by a cable as...Ch. 8.1 - A cord is attached to and partially wound around a...Ch. 8.1 - A 40-kg packing crate must be moved to the left...Ch. 8.1 - Determine whether the block shown is in...Ch. 8.1 - Prob. 8.2PCh. 8.1 - Prob. 8.3PCh. 8.1 - Prob. 8.4PCh. 8.1 - Prob. 8.5PCh. 8.1 - The 20-lb block A hangs from a cable as shown....
Ch. 8.1 - The 10-kg block is attached to link AB and rests...Ch. 8.1 - Considering only values of less than 90,...Ch. 8.1 - The coefficients of friction between the block and...Ch. 8.1 - The coefficients of friction between the block and...Ch. 8.1 - The 50-lb block A and the 25-lb block B are...Ch. 8.1 - The 50-lb block A and the 25-lb block B are...Ch. 8.1 - Three 4-kg packages A, B, and C are placed on a...Ch. 8.1 - Solve Prob. 8.13 assuming that package B is placed...Ch. 8.1 - A uniform crate with a mass of 30 kg must be moved...Ch. 8.1 - A worker slowly moves a 50-kg crate to the left...Ch. 8.1 - Prob. 8.17PCh. 8.1 - A 200-lb sliding door is mounted on a horizontal...Ch. 8.1 - Prob. 8.19PCh. 8.1 - Solve Prob. 8.19 assuming that the coefficients of...Ch. 8.1 - Prob. 8.21PCh. 8.1 - The cylinder shown has a weight W and radius r,...Ch. 8.1 - The 10-lb uniform rod AB is held in the position...Ch. 8.1 - In Prob. 8.23, determine the largest value of P...Ch. 8.1 - A 6. 5-m ladder AB leans against a wall as shown....Ch. 8.1 - A 6. 5-m ladder AB leans against a wall as shown....Ch. 8.1 - The press shown is used to emboss a small seal at...Ch. 8.1 - The machine base shown has a mass of 75 kg and is...Ch. 8.1 - The 50-lb plate ABCD is attached at A and D to...Ch. 8.1 - In Prob. 8.29, determine the range of values of...Ch. 8.1 - A window sash weighing 10 lb is normally supported...Ch. 8.1 - A 500-N concrete block is to be lifted by the pair...Ch. 8.1 - Prob. 8.33PCh. 8.1 - A driver starts the engine of an automobile that...Ch. 8.1 - Prob. 8.35PCh. 8.1 - Prob. 8.36PCh. 8.1 - A 1.2-m plank with a mass of 3 kg rests on two...Ch. 8.1 - Two identical uniform boards, each with a weight...Ch. 8.1 - Prob. 8.39PCh. 8.1 - Prob. 8.40PCh. 8.1 - A 10-ft beam, weighing 1200 lb, is to be moved to...Ch. 8.1 - (a) Show that the beam of Prob. 8.41 cannot be...Ch. 8.1 - Two 8-kg blocks A and B resting on shelves are...Ch. 8.1 - A slender steel rod with a length of 225 mm is...Ch. 8.1 - In Prob. 8.44, determine the smallest value of ...Ch. 8.1 - Two slender rods of negligible weight are...Ch. 8.1 - Two slender rods of negligible weight are...Ch. 8.2 - The machine part ABC is supported by a...Ch. 8.2 - Solve Prob. 8.48 assuming that the wedge is moved...Ch. 8.2 - 8.50 and 8.51 Two 6 wedges of negligible weight...Ch. 8.2 - 8.50 and 8.51 Two 6 wedges of negligible weight...Ch. 8.2 - The elevation of the end of the steel beam...Ch. 8.2 - Prob. 8.53PCh. 8.2 - Block A supports a pipe column and rests as shown...Ch. 8.2 - Block A supports a pipe column and rests as shown...Ch. 8.2 - Block A supports a pipe column and rests as shown...Ch. 8.2 - A 200-lb block rests as shown on a wedge of...Ch. 8.2 - A 15 wedge is forced into a saw cut to prevent...Ch. 8.2 - A 12 wedge is used to spread a split ring. The...Ch. 8.2 - The spring of the door latch has a constant of 1.8...Ch. 8.2 - Prob. 8.61PCh. 8.2 - Prob. 8.62PCh. 8.2 - Prob. 8.63PCh. 8.2 - A 15 wedge is forced under a 50-kg pipe as shown....Ch. 8.2 - A 15 wedge is forced under a 50-kg pipe as shown....Ch. 8.2 - Prob. 8.66PCh. 8.2 - Prob. 8.67PCh. 8.2 - Derive the following formulas relating the load W...Ch. 8.2 - The square-threaded worm gear shown has a mean...Ch. 8.2 - Prob. 8.70PCh. 8.2 - High-strength bolts are used in the construction...Ch. 8.2 - The position of the automobile jack shown is...Ch. 8.2 - For the jack of Prob. 8.72, determine the...Ch. 8.2 - Prob. 8.74PCh. 8.2 - Prob. 8.75PCh. 8.2 - Prob. 8.76PCh. 8.3 - A lever of negligible weight is loosely fitted...Ch. 8.3 - A 6-in.-radius pulley of weight 5 lb is attached...Ch. 8.3 - 8.79 and 8.80 The double pulley shown is attached...Ch. 8.3 - Prob. 8.80PCh. 8.3 - 8.81 and 8.82 The double pulley shown is attached...Ch. 8.3 - 8.81 and 8.82 The double pulley shown is attached...Ch. 8.3 - The block and tackle shown are used to raise a...Ch. 8.3 - The block and tackle shown are used to lower a...Ch. 8.3 - A scooter is to be designed to roll down a 2...Ch. 8.3 - The link arrangement shown is frequently used in...Ch. 8.3 - 8.87 and 8.88 A lever AB of negligible weight is...Ch. 8.3 - 8.87 and 8.88 A lever AB of negligible weight is...Ch. 8.3 - 8.89 and 8.90 A lever AB of negligible weight is...Ch. 8.3 - 8.89 and 8.90 A lever AB of negligible weight is...Ch. 8.3 - A loaded railroad car has a mass of 30 Mg and is...Ch. 8.3 - Prob. 8.92PCh. 8.3 - A 50-lb electric floor polisher is operated on a...Ch. 8.3 - The frictional resistance of a thrust bearing...Ch. 8.3 - Assuming that bearings wear out as indicated in...Ch. 8.3 - Assuming that the pressure between the surfaces of...Ch. 8.3 - Solve Prob. 8.93 assuming that the normal force...Ch. 8.3 - Determine the horizontal force required to move a...Ch. 8.3 - Knowing that a 6-in.-diameter disk rolls at a...Ch. 8.3 - A 900-kg machine base is rolled along a concrete...Ch. 8.3 - Solve Prob. 8.85 including the effect of a...Ch. 8.3 - Solve Prob. 8.91 including the effect of a...Ch. 8.4 - A rope having a weight per unit length of 0.4...Ch. 8.4 - A hawser is wrapped two full turns around a...Ch. 8.4 - Two cylinders are connected by a rope that passes...Ch. 8.4 - Two cylinders are connected by a rope that passes...Ch. 8.4 - The coefficient of static friction between block B...Ch. 8.4 - The coefficient of static friction S is the same...Ch. 8.4 - A band belt is used to control the speed of a...Ch. 8.4 - The setup shown is used to measure the output of a...Ch. 8.4 - The setup shown is used to measure the output of a...Ch. 8.4 - A flat belt is used to transmit a couple from drum...Ch. 8.4 - A flat belt is used to transmit a couple from...Ch. 8.4 - Prob. 8.114PCh. 8.4 - The speed of the brake drum shown is controlled by...Ch. 8.4 - Prob. 8.116PCh. 8.4 - The speed of the brake drum shown is controlled by...Ch. 8.4 - Bucket A and block C are connected by a cable that...Ch. 8.4 - Solve Prob. 8.118 assuming that drum B is frozen...Ch. 8.4 - Prob. 8.120PCh. 8.4 - 8.121 and 8.123 A cable is placed around three...Ch. 8.4 - Prob. 8.122PCh. 8.4 - 8.121 and 8.123 A cable is placed around three...Ch. 8.4 - A recording tape passes over the 20-mm-radius...Ch. 8.4 - Solve Prob. 8.124 assuming that the idler drum C...Ch. 8.4 - Prob. 8.126PCh. 8.4 - The axle of the pulley is frozen and cannot rotate...Ch. 8.4 - Prob. 8.128PCh. 8.4 - Prob. 8.129PCh. 8.4 - Prove that Eqs. (8.13) and (8.14) are valid for...Ch. 8.4 - Prob. 8.131PCh. 8.4 - Solve Prob. 8.112 assuming that the flat belt and...Ch. 8.4 - Solve Prob. 8.113 assuming that the flat belt and...Ch. 8 - 8.134 and 8.135 The coefficients of friction are S...Ch. 8 - 8.134 and 8.135 The coefficients of friction are S...Ch. 8 - A 120-lb cabinet is mounted on casters that can be...Ch. 8 - Prob. 8.137RPCh. 8 - The hydraulic cylinder shown exerts a force of 3...Ch. 8 - Prob. 8.139RPCh. 8 - Bar AB is attached to collars that can slide on...Ch. 8 - Two 10 wedges of negligible weight are used to...Ch. 8 - A 10 wedge is used to split a section of a log....Ch. 8 - In the gear-pulling assembly shown, the...Ch. 8 - A lever of negligible weight is loosely fitted...Ch. 8 - In the pivoted motor mount shown, the weight W of...
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- CHAIN DRIVE DESIGN Initial Input Data: Application: Garage Door Opener Drive type: AC Motor Driven machine Chain and Sprocket to pull the door up Degrees per Radian: 57.2958 degrees Sprocket Diameter: D = 1.690 in Number of strands: Chain number: 1 40 Service factor: 1.3 Table 7-10 No. of teeth Computed Data: Actual Motor Power Input: 0.000 hp Sprocket Speed (for sprocket attached to gear shaft) Design power: 0.00 rpm 0 hp 11 12 0.06 0.15 0.29 0.56 0.99 1.09 1.61 2.64 TABLE 7-7 Horsepower Ratings-Single Strand Roller Chain No. 40 0.500 inch pitch 10 25 50 100 180 200 300 500 700 900 1000 1: 0.06 0.14 0.27 0.52 0.91 1.00 1.48 2.42 3.34 4.25 4.70 ! 3.64 4.64 5.13 13 0.07 0.16 0.31 0.61 1.07 1.19 1.75 2.86 3.95 5.02 5.56 Design Decisions-Chain Type and Teeth Numbers: 14 Chain number: Use Table 7-7 Chain pitch: p = in 15 Number of Teeth: N = Per Table 7-7 16 0.08 0.20 0.39 0.75 1.32 1.46 2.15 3.52 0.07 0.17 0.34 0.66 1.15 1.28 1.88 3.08 0.08 0.19 0.36 0.70 1.24 1.37 2.02 3.30 4.55 5.80…arrow_forwardInput Data: Torque needed to overcome rolling friction in rollers, slides and other moving parts, except for Motor and Worm Gear the worm gear T₁ = Length of travel of door: Time for door to open or close: LD = 50 lb-in. 90 in t= 12.5 seconds Pitch diameter for chain sprocket: DPC 1.690 in Weight of Door: P = No. of worm threads: Nw = Worm Pitch diameter: Dw Diametral pitch: Pd Normal pressure angle: Degrees per Radian: Number of gear teeth: Calculated Data: Linear velocity of door and chain (in/sec): Linear velocity of door and chain (ft/min): Output Speed of Gear and Sprocket: Upward Force due to Weight of Door: Фо = = NG= 240 lb 2 1.250 in 12 14.5 degrees 57.2958 degrees 28 Vα= in/sec VC= ft/min NG = rpm FD lb Net Upward Force on Door: Fou lb Torque on gear ignoring rolling friction: TG = lb-in. Formula = FDU FD-2 x Fo (note: Fo is the Max Operating load of the extension springs). This is also the initial tension in the chain. TG = FDU X DPC/2 This is the also the torque on the…arrow_forwardQ5/A: A car with a track of 1.5 m and a wheelbase of 2.9 m has a steering gear mechanism of the Ackermann type. The distance between the front stub axle pivots is 1.3 m. The length of each track arm is 150 mm, and the length of the track rod is 1.2 m. Find the angle turned through by the outer wheel if the angle turned through by the inner wheel is 30°. (6 Marks) Q5/B: Write True on the correct sentences and False on the wrong sentences listed below:- 1- In automobiles, the power is transmitted from the gearbox to the differential through bevel gears. 2- The minimum radius circle drawn to the cam profile is called the base circle. 3- The Proell governor, compared to the Porter governor, has less lift at the same speed. 4- The balancing of rotating and reciprocating parts of an engine is necessary when it runs at a slow speed. (6.5 Marks) ***Best of Luck *** جامعة بابل UNIVERSITY OF BABYLON Examiner: Mohanad R. Hameed Head of Department: Dr. Dhyai H. Jawadarrow_forward
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