Explanation Consider the provided argument, ‘When we roll two indistinguishable dice, the number of possible outcomes is 21 and the number of outcomes in which both numbers are the same is 6. Hence, the probability of throwing a double is 6 21 = 2 7 ’. According to the argument, the outcomes are equally likely, but it is not s because the sample space for rolling two indistinguishable dice, Since, the dice are distinguishable, thus, the sample space for the toss of two distinguishable dice is S = { ( 1 , 1 ) , ( 1 , 2 ) , ( 1 , 3 ) , ( 1 , 4 ) ( 1 , 5 ) ( 1 , 6 ) ( 2 , 1 ) , ( 2 , 2 ) , ( 2 , 3 ) , ( 2 , 4 ) ( 2 , 5 ) ( 2 , 6 ) ( 3 , 1 ) , ( 3 , 2 ) , ( 3 , 3 ) , ( 3 , 4 ) ( 3 ,

Finite Mathematics and Applied Calculus (MindTap Course List)

7th Edition

ISBN: 9781337274203

Author: Stefan Waner, Steven Costenoble

Publisher: Cengage Learning

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Question

Chapter 8.4, Problem 50E

To determine

The incorrect part in the argument, ‘When we roll two indistinguishable dice, the number of possible outcomes is 21 and the number of outcomes in which both numbers are the same is 6. Hence, the probability of throwing a double is 621=27’.

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Chapter 8.4, Problem 49E

Chapter 8.4, Problem 51E

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Chapter 8 Solutions

Finite Mathematics and Applied Calculus (MindTap Course List)

Ch. 8.1 - In Exercises 118, describe the sample space S of...Ch. 8.1 - Prob. 2E Ch. 8.1 - In Exercises 118, describe the sample space S of...Ch. 8.1 - Prob. 4E Ch. 8.1 - In Exercises 118, describe the sample space S of...Ch. 8.1 - Prob. 6E Ch. 8.1 - In Exercises 118, describe the sample space S of...Ch. 8.1 - Prob. 8E Ch. 8.1 - In Exercises 118, describe the sample space S of...Ch. 8.1 - Prob. 10E

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The incorrect part in the argument, ‘When we roll two indistinguishable dice, the number of possible outcomes is 21 and the number of outcomes in which both numbers are the same is 6. Hence, the probability of throwing a double is 6 21 = 2 7 ’.

Solution Summary: The author explains that the experiment considers all outcomes to be equally likely.

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The incorrect part in the argument, ‘When we roll two indistinguishable dice, the number of possible outcomes is 21 and the number of outcomes in which both numbers are the same is 6. Hence, the probability of throwing a double is 621=27’.

Want to see the full answer?

Chapter 8 Solutions