Chapter 8.3, Problem 7E

Explanation of volume revolving around x and y axis formula

Determine the volume of the solid created by rotating the region bounded by y = x³, y= 125, the x-axis and the y-axis about the y-axis. The region is shown below. 120- 100어 80어 60어 40어 20어 -1 1 3 4 6 V = Number

Calculus 2 Having trouble with how to find the area of the region enclosed by the curves (blue highlighted area).  Please help. Thank you, Braiden

Find the volume generated by revolving the regionbounded by y=−x^4+3x^3, y=0  revolving about the x − axis. Show the element of area on the grid provided.

The volume of the solid obtained by rotating the region enclosed by x=0, y=1, x=y^5   Whats the volume and cubic units?

The base of a solid is the region enclosed by the circle x^2 + y^2 =9. Cross-sections perpendicular to the x-axis are isosceles right triangles with the hypotenuse in the base. Find the volume of the solid.

Calculate exactly the volume of the solid obtained by rotating the area delimited by y=(x-2)^2 and the coordinate axes around the line y = 5.

ans: 54pi^2

Determine the volume of the solid formed when a circle that passes through the points (l , 3), (3 , 1) and (1 , -1) is revolved about a line which passes through the points (-2 , 3) and (-4, 0).