Explanation Given: The current I in a circuit with voltage E , resistance R , capacitive reactance X c , and inductive reactance X L , with E = 12 ( cos 25 ° + i sin 25 ° ) , R = 3 , X L = 4 , and X C = 6 , is given by I = E R + ( X L − X C ) i Calculation: First, change E to the rectangular form. Since there is no specific reference angle for 25 ° , exact values for cos 25 ° and sin 25 ° can’t be found. So, there approximate values can be found with the help of a calculator: cos 25 ° = 0.9063077 sin 25 ° = 0.42261826 So, rectangular form of E is E = 12 ( cos 25 ° + i sin 25 ° ) = 12 ( 0.9063077 + 0.42261826 i ) = 10.875692 + 5 .07141912i Write to one decimal: E = 10.9 + 5.1 i Now, current is provided by I = E R + ( X L − X C ) i where E = 10

Trigonometry plus MyLab Math with Pearson eText -- Access Card Package (11th Edition)

11th Edition

ISBN: 9780134307008

Author: Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Publisher: PEARSON

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Chapter 8.3, Problem 42E

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To calculate: The current in an electric circuit using the given conditions if the current I in a circuit with voltage E, resistance R, capacitive reactance Xc, and inductive reactance XL, with E=12(cos25°+isin25°), R=3, XL=4, and XC=6, is given by

I=ER+(XL−XC)i

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Chapter 8.3, Problem 41E

Chapter 8.3, Problem 43E

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Chapter 8 Solutions

Trigonometry plus MyLab Math with Pearson eText -- Access Card Package (11th Edition)

Ch. 8.1 - CONCEPT PREVIEW Fill in the blank(s) to correctly...Ch. 8.1 - CONCEPT PREVIEW Fill in the blank(s) to correctly...Ch. 8.1 - CONCEPT PREVIEW Fill in the blank(s) to...Ch. 8.1 - CONCEPT PREVIEW Fill in the blank(s) to correctly...Ch. 8.1 - Prob. 5E Ch. 8.1 - Prob. 6E Ch. 8.1 - Prob. 7E Ch. 8.1 - Prob. 8E Ch. 8.1 - Prob. 9E Ch. 8.1 - Prob. 10E

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The current in an electric circuit using the given conditions if the current I in a circuit with voltage E , resistance R , capacitive reactance X c , and inductive reactance X L , with E = 12 ( cos 25 ° + i sin 25 ° ) , R = 3 , X L = 4 , and X C = 6 , is given by I = E R + ( X L − X C ) i

Solution Summary: The author calculates the current in an electric circuit using the given conditions. Since there is no specific reference angle for 25°, approximate values can be found with the help of a calculator.

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To calculate: The current in an electric circuit using the given conditions if the current I in a circuit with voltage E, resistance R, capacitive reactance Xc, and inductive reactance XL, with E=12(cos25°+isin25°), R=3, XL=4, and XC=6, is given by

I=ER+(XL−XC)i

Want to see the full answer?

Chapter 8 Solutions

The current in an electric circuit using the given conditions if the current I in a circuit with voltage E , resistance R , capacitive reactance X c , and inductive reactance X L , with E = 12 ( cos 25 ° + i sin 25 ° ) , R = 3 , X L = 4 , and X C = 6 , is given by I = E R + ( X L − X C ) i

Solution Summary: The author calculates the current in an electric circuit using the given conditions. Since there is no specific reference angle for 25°, approximate values can be found with the help of a calculator.

Concept explainers

Videos

To calculate: The current in an electric circuit using the given conditions if the current I in a circuit with voltage E, resistance R, capacitive reactance Xc, and inductive reactance XL, with E=12(cos25°+isin25°), R=3, XL=4, and XC=6, is given by I=ER+(XL−XC)i

Want to see the full answer?

Chapter 8 Solutions

To calculate: The current in an electric circuit using the given conditions if the current I in a circuit with voltage E, resistance R, capacitive reactance Xc, and inductive reactance XL, with E=12(cos25°+isin25°), R=3, XL=4, and XC=6, is given by

I=ER+(XL−XC)i