Explanation Given information: The given function is f ( x ) = ln x and the interval is [ 1 , 4 ] . Formula used: Assume that f ( x ) ≥ 0 and f ′ exists and continuous on the interval [ a , b ] . The surface area S of revolution about the y -axis over the interval is given by S = 2 π ∫ a b x 1 + [ f ′ ( x ) ] 2 d x The power rule of indefinite integrals. ∫ 1 + x 2 d x = 1 2 x x 2 + 1 + 1 2 ln | x + 1 + x 2 | + C Calculation: Consider the given function. y = f ( x ) = ln x Differentiate the above function with respect to x . f ′ ( x ) = 1 x The given interval is [ 1 , 4 ] . Here, a = 0 , b = 4 For 1 ≤ x ≤ 4 , x ≥ 0 and f ′ exists and continuous on [ 1 , 4 ] . Now calculate the surface area of revolution about y -axis over the interval [ 1 , 4 ] as shown below

Loose-leaf Version For Calculus: Early Transcendentals

4th Edition

ISBN: 9781319055912

Author: Jon Rogawski, Colin Adams, Robert Franzosa

Publisher: W. H. Freeman

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Chapter 8.2, Problem 58E

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Thesurface area of revolution about the y -axis over the interval [1,4] for the given function.

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Chapter 8.2, Problem 57E

Chapter 8.2, Problem 59E

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Chapter 8 Solutions

Loose-leaf Version For Calculus: Early Transcendentals

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Thesurface area of revolution about the y -axis over the interval [ 1 , 4 ] for the given function.

Solution Summary: The author calculates the surface area of revolution about the y -axis over the interval for the given function.

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To compute:

Thesurface area of revolution about the y -axis over the interval [1,4] for the given function.

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Chapter 8 Solutions

Thesurface area of revolution about the y -axis over the interval [ 1 , 4 ] for the given function.

Solution Summary: The author calculates the surface area of revolution about the y -axis over the interval for the given function.

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To compute: Thesurface area of revolution about the y -axis over the interval [1,4] for the given function.

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Chapter 8 Solutions

To compute:

Thesurface area of revolution about the y -axis over the interval [1,4] for the given function.