Explanation Given information: We have given an equation of Parabola y = 3 x 2 + 6 x + 2 . Calculation: The equation of parabola is y = 3 x 2 + 6 x + 2 . It can also be written as y + 1 = 3 x 2 + 6 x + 3 ⇒ ( y + 1 ) = 3 ( x + 1 ) 2 ⇒ ( x + 1 ) 2 = 1 3 ( y + 1 ) ....(1) Comparing with ( x − h ) 2 = 4 p ( y − k ) we get, h = − 1 , k = − 1 a n d p = 1 12

Precalculus: A Unit Circle Approach, Books a la Carte Edition plus MyMathLab with Pearson eText -- Access Card Package (2nd Edition)

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ISBN: 9780321869401

Author: J. S. Ratti

Publisher: PEARSON

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Chapter 8.2, Problem 40E

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To find the vertex, focus and directrix of the parabola y=3x2+6x+2.

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Chapter 8.2, Problem 39E

Chapter 8.2, Problem 41E

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Precalculus: A Unit Circle Approach, Books a la Carte Edition plus MyMathLab with Pearson eText -- Access Card Package (2nd Edition)

Ch. 8.2 - Prob. 1E Ch. 8.2 - Prob. 2E Ch. 8.2 - Prob. 3E Ch. 8.2 - Prob. 4E Ch. 8.2 - Prob. 5E Ch. 8.2 - Prob. 6E Ch. 8.2 - Prob. 7E Ch. 8.2 - Prob. 8E Ch. 8.2 - Prob. 9E Ch. 8.2 - Prob. 10E

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To find the vertex, focus and directrix of the parabola y = 3 x 2 + 6 x + 2 .

Solution Summary: The author calculates the parabola's vertex, focus, and directrix using y=3x2+6x+2.

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To find the vertex, focus and directrix of the parabola y=3x2+6x+2.

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