a. Explanation Given info: The claim of the test is the percentage of blue M&Ms is greater than 5% with the P -value is 0.0010 and significance level is α = 0.05 . Calculation: Here, the test claims that the percentage of blue M&Ms is greater than 5% which represents the alternative hypothesis. Thus, the null hypothesis is the percentage of blue M&Ms is 5%. The hypotheses are given below: Null hypothesis: H 0 : p = 0.05 That is, there is no sufficient evidence to support the claim that the percentage of blue M&Ms is greater than 5%. Alternative hypothesis: H 1 : p > 0.05 That is, there is sufficient evidence to support the claim that the percentage of blue M&Ms is greater than 5% b. To determine To conclude: About the original claim without using technical terms or symbols.

12th Edition

ISBN: 9780321836960

Author: Mario F. Triola

Publisher: PEARSON

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2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.

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Chapter 8.2, Problem 25BSC

To determine

To conclude: About the null hypothesis.

To determine

To conclude: About the original claim without using technical terms or symbols.

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Chapter 8.2, Problem 24BSC

Chapter 8.2, Problem 26BSC

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To conclude: About the null hypothesis.

Solution Summary: The author concludes that the null hypothesis is rejected at 5% level.

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To conclude: About the null hypothesis.

To conclude: About the original claim without using technical terms or symbols.

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Chapter 8 Solutions