CALCULUS:GRAPHICAL...,AP ED.-W/ACCESS
5th Edition
ISBN: 9780133314564
Author: Finney
Publisher: SAVVAS L
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Students have asked these similar questions
Determine the interval(s) where the function f(x) = −(x − 5)² is increasing.
Submit your answer in interval notation. For example, if the interval is all values of a greater than or equal to 2, then your
response should be [2, ∞). If there is no interval where the function is increasing, then enter the symbol Ø (found in the
"Sets" keyboard below the answer box). If necessary, you can represent the union of intervals using the U symbol (also
found in the "Sets" keyboard).
Provide your answer below:
f(x) is increasing in the interval
Show that cosecant is an odd function.
Determine the domain of the function
f(x) = =
√x
x² - 64
(Give your answer as an interval in the form (*, *). Use the symbol ∞o for infinity, U for combining intervals, and an appropriate
type of parenthesis " (",") ", " [","] " depending on whether the interval is open or closed. Enter Ø if the interval is empty.
Express numbers in exact form. Use symbolic notation and fractions where needed.)
Write co for positive infinity (without a '+' sign).
domain:
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Similar questions
- Consider the function: g(z) = with the domain IR\{8} (i.e. all real numbers except 8) and the image R\{1} (i.e. all real numbers I+10 except 1). Find the expression for the inverse function g(r). Select one: O not in the list O (10+8x)/(x-1) O 10+8x O (10+8x)/(x+1) O (x-8)/(x+10)arrow_forwardSuppose f(x) = x² + 3x + 1. In this problem, we will show that f has exactly one root (or zero) in the interval [-4,-1]. (a) First, we show that f has a root in the interval (-4,-1). Since f is a choose function on the interval [-4, -1] and f(-4)= and f(-1) =, the graph of y = f(x) must cross the x-axis at some point in the interval (-4,-1) by the ◆. Thus, f has at least choose one root in the interval [—4, -1]. (b) Second, we show that f cannot have more than one root in the interval [−4, -1] by a thought experiment. Suppose that there were two roots x = a and x = b in the interval [-4, −1] with a < b. Then f(a) = f(b) = Since fis choose on the interval [-4,-1] and choose on the interval (-4,-1), by choose there would exist a point c in interval (a, b) so that f'(c) = 0. However, the only solution to f'(x) = 0 is x = not in the interval (a, b), or in [−4, -1]. Thus, f cannot have more than one root in [−4, −1]. 0 which isarrow_forwardSuppose that f has a domain of [5, 13] and a range of [6, 16]. (a) What are the domain and range of the function y = f(x) + 2? (Use symbolic notation and fractions where needed. Give your answers as intervals in the form (*, *). Use the symbol ∞ for infinity and the appropriate type of parenthesis "(", ")", "[", or "]" depending on whether the interval is open or closed.) D= R =arrow_forward
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