Chapter 8.1, Problem 60E

To determine

To Write: The formula for the sum of the cubes of first $n$ terms.

Answer to Problem 60E

  $\frac{1}{4}{n}^2{(n+1)}^2$

Explanation of Solution

Given: In this section you learned the following formula.

  

Formula for the sum of the cubes of first $n$ terms.

  ${\displaystyle \sum _{i=1}^n{i}^3}=\frac{1}{4}{n}^2{(n+1)}^2$

Hence, $\frac{1}{4}{n}^2{(n+1)}^2$