To determine The integral ∫ 1 20 u d v . Explanation Given: The value of ∫ 1 20 v d u = − 1 where u and v are differentiable function and its functional values are shown in the below table. x u ( x ) v ( x ) 1 5 − 2 20 15 6 Formula used: Integration by parts: “If u and v are differentiable functions, then ∫ u d v = u v − ∫ v d u .” Calculation: From the table, observe that u ( 1 ) = 5 , u ( 20 ) = 15 , v ( 1 ) = − 2 and v ( 20 ) = 6 . Find the value of ∫ 1 20 u d v . Use the integration by parts formula and write the integral as, ∫ 1 20 u d v = [ u v ] 1 20 − ∫ 1 20 v d u . Substitute ∫ 1 20 v d u = − 1 and simplify further

Calculus with Applications (11th Edition)

11th Edition

ISBN: 9780321979421

Author: Margaret L. Lial, Raymond N. Greenwell, Nathan P. Ritchey

Publisher: PEARSON

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Differential Equations

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Chapter 8.1, Problem 32E

To determine

The integral ∫120udv .

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Chapter 8.1, Problem 31E

Chapter 8.1, Problem 33E

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Calculus with Applications (11th Edition)

Ch. 8.1 - YOUR TURN 1 Find Ch. 8.1 - YOUR TURN 2 Find Ch. 8.1 - YOUR TURN 3 Find Ch. 8.1 - YOUR TURN 4 Find . Ch. 8.1 - YOUR TURN 5 Find Ch. 8.1 - Prob. 1WE Ch. 8.1 - Find the following. W2. Ch. 8.1 - Find the following. W3. Ch. 8.1 - Find the following. W4. Ch. 8.1 - Use integration by parts to find the integrals in...

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