Explanation Given Information: The system of linear equations is: { 3 y − z = − 1 x + 5 y − z = − 4 − 3 x + 6 y + 2 z = 11 Formula used: Gauss elimination method. Calculation: A system of linear equations can be solved with the help of matrices. It is solved with the help of augmented matrix. A matrix, which is divided into two groups divided by a vertical bar with the coefficients of the variable on one side and constants on the other side, is called an augmented matrix. Row indicates coefficient and constant from an equation whereas column indicates all the coefficient of a variable. The coefficient of the missing variable is used as 0 . Augmented matrix for the provided system of equation is written as follows: [ 0 3 − 1 − 1 1 5 − 1 − 4 − 3 6 2 11 ] Gauss elimination method is used to solve the system of linear equations by turning the augmented matrix in row echelon form. Perform the operations as follows: Replace R 1 by R 1 + R 2 , to get, [ 1 8 − 2 − 5 1 5 − 1 − 4 − 3 6 2 11 ] Replace R 2 by − R 1 + R 2 to get, [ 1 8 − 2 − 5 0 − 3 1 1 − 3 6 2 11 ] Replace R 2 by − 1 3 R 2 to get, [ 1 8 − 2 − 5 0 1 1 3 1 3 − 3 6 2 11 ] Replace R 3 by 3 R 1 + R 3 to get, [ 1 8 − 2 − 5 0 1 1 3 <

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ISBN: 9781269417358

Author: Blitzer

Publisher: PEARSON C

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‘Matrices’ is the plural form of the word matrix, and it is basically a spreadsheet in the form of a box. In mathematics, various functions can be carried out with matrices. Generally, a matrix comes in the shape of a square or rectangle. The elements ar…

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Chapter 8.1, Problem 24PE

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To calculate: The solution of the system of linear equations 3y−z=−1,x+5y−z=−4,−3x+6y+2z=11 by Gauss-Jordan method.

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Chapter 8.1, Problem 23PE

Chapter 8.1, Problem 25PE

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Chapter 8 Solutions

PRECALCULUS CUSTOM W/MYMTHLAB >IC<

Ch. 8.1 - Check Point 1 Write the augmented matrix for the...Ch. 8.1 - Check Point 2 Use the matrix ...Ch. 8.1 - Check Point 3 Use matrices to solve the system:...Ch. 8.1 - Check Point 4 Use matrices to solve the system:...Ch. 8.1 - Check Point 5 Solve the system in Check Point. 3...Ch. 8.1 - Prob. 1CVC Ch. 8.1 - Fill in each blank so that the resulting statement...Ch. 8.1 - Prob. 3CVC Ch. 8.1 - Prob. 4CVC Ch. 8.1 - Fill in each blank so that the resulting statement...

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The solution of the system of linear equations 3 y − z = − 1 , x + 5 y − z = − 4 , − 3 x + 6 y + 2 z = 11 by Gauss-Jordan method.

Solution Summary: The author explains the Gauss-Jordan method used to solve the system of linear equations.

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To calculate: The solution of the system of linear equations 3y−z=−1,x+5y−z=−4,−3x+6y+2z=11 by Gauss-Jordan method.

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Chapter 8 Solutions