Explanation Given information: A function is given by p ( t ) = 1 r e − t r on the interval [ 0 , ∞ ) . Formula used: The indefinite integral can be calculated as shown below. ∫ e − a t d t = e − a t − a + C Calculation: Let us consider the given function. p ( t ) = 1 r e − t r Now let us evaluate the integral ∫ 0 ∞ p ( t ) d t as follows: ∫ 0 ∞ p ( t ) d t = ∫ 0 ∞ 1 r e − t / r d t = lim A → ∞ ∫ 0 A

4th Edition

ISBN: 9781319050740

Author: Jon Rogawski, Colin Adams, Robert Franzosa

Publisher: W. H. Freeman

See similar textbooks

Concept explainers

Continuous Probability Distributions

Probability distributions are of two types, which are continuous probability distributions and discrete probability distributions. A continuous probability distribution contains an infinite number of values. For example, if time is infinite: you could co…

Normal Distribution

Suppose we had to design a bathroom weighing scale, how would we decide what should be the range of the weighing machine? Would we take the highest recorded human weight in history and use that as the upper limit for our weighing scale? This may not be a…

Videos

Question

Chapter 8.1, Problem 12E

To determine

To show:

That p(t) satisfies the condition ∫0∞p(t)dt=1 for all r>0.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 8.1, Problem 11E

Chapter 8.1, Problem 13E

Students have asked these similar questions

1/ Solve the following: 1 x + X + cos(3X) -75 -1 2 2 (5+1) e 5² + 5 + 1 3 L -1 1 5² (5²+1) 1 5(5-5)

I need expert handwritten solution.to this integral

How to understand and learn Laurent's serial and what's the point of Laurent's serial And what are the steps of a smooth solution for Laurent

Chapter 8 Solutions

Calculus: Early Transcendentals

Ch. 8.1 - Prob. 1PQ Ch. 8.1 - Prob. 2PQ Ch. 8.1 - Prob. 3PQ Ch. 8.1 - Prob. 1E Ch. 8.1 - Prob. 2E Ch. 8.1 - Prob. 3E Ch. 8.1 - Prob. 4E Ch. 8.1 - Prob. 5E Ch. 8.1 - Prob. 6E Ch. 8.1 - Prob. 7E

Ch. 8.1 - Prob. 8E Ch. 8.1 - Prob. 9E Ch. 8.1 - Prob. 10E Ch. 8.1 - Prob. 11E Ch. 8.1 - Prob. 12E Ch. 8.1 - Prob. 13E Ch. 8.1 - Prob. 14E Ch. 8.1 - Prob. 15E Ch. 8.1 - Prob. 16E Ch. 8.1 - Prob. 17E Ch. 8.1 - Prob. 18E Ch. 8.1 - Prob. 19E Ch. 8.1 - Prob. 20E Ch. 8.1 - Prob. 21E Ch. 8.1 - Prob. 22E Ch. 8.1 - Prob. 23E Ch. 8.1 - Prob. 24E Ch. 8.1 - Prob. 25E Ch. 8.1 - Prob. 26E Ch. 8.1 - Prob. 27E Ch. 8.1 - Prob. 28E Ch. 8.1 - Prob. 29E Ch. 8.1 - Prob. 30E Ch. 8.1 - Prob. 31E Ch. 8.1 - Prob. 32E Ch. 8.2 - Prob. 1PQ Ch. 8.2 - Prob. 2PQ Ch. 8.2 - Prob. 3PQ Ch. 8.2 - Prob. 4PQ Ch. 8.2 - Prob. 5PQ Ch. 8.2 - Prob. 1E Ch. 8.2 - Prob. 2E Ch. 8.2 - Prob. 3E Ch. 8.2 - Prob. 4E Ch. 8.2 - Prob. 5E Ch. 8.2 - Prob. 6E Ch. 8.2 - Prob. 7E Ch. 8.2 - Prob. 8E Ch. 8.2 - Prob. 9E Ch. 8.2 - Prob. 10E Ch. 8.2 - Prob. 11E Ch. 8.2 - Prob. 12E Ch. 8.2 - Prob. 13E Ch. 8.2 - Prob. 14E Ch. 8.2 - Prob. 15E Ch. 8.2 - Prob. 16E Ch. 8.2 - Prob. 17E Ch. 8.2 - Prob. 18E Ch. 8.2 - Prob. 19E Ch. 8.2 - Prob. 20E Ch. 8.2 - Prob. 21E Ch. 8.2 - Prob. 22E Ch. 8.2 - Prob. 23E Ch. 8.2 - Prob. 24E Ch. 8.2 - Prob. 25E Ch. 8.2 - Prob. 26E Ch. 8.2 - Prob. 27E Ch. 8.2 - Prob. 28E Ch. 8.2 - Prob. 29E Ch. 8.2 - Prob. 30E Ch. 8.2 - Prob. 31E Ch. 8.2 - Prob. 32E Ch. 8.2 - Prob. 33E Ch. 8.2 - Prob. 34E Ch. 8.2 - Prob. 35E Ch. 8.2 - Prob. 36E Ch. 8.2 - Prob. 37E Ch. 8.2 - Prob. 38E Ch. 8.2 - Prob. 39E Ch. 8.2 - Prob. 40E Ch. 8.2 - Prob. 41E Ch. 8.2 - Prob. 42E Ch. 8.2 - Prob. 43E Ch. 8.2 - Prob. 44E Ch. 8.2 - Prob. 45E Ch. 8.2 - Prob. 46E Ch. 8.2 - Prob. 47E Ch. 8.2 - Prob. 48E Ch. 8.2 - Prob. 49E Ch. 8.2 - Prob. 50E Ch. 8.2 - Prob. 51E Ch. 8.2 - Prob. 52E Ch. 8.2 - Prob. 53E Ch. 8.2 - Prob. 54E Ch. 8.2 - Prob. 55E Ch. 8.2 - Prob. 56E Ch. 8.2 - Prob. 57E Ch. 8.2 - Prob. 58E Ch. 8.2 - Prob. 59E Ch. 8.2 - Prob. 60E Ch. 8.2 - Prob. 61E Ch. 8.2 - Prob. 62E Ch. 8.2 - Prob. 63E Ch. 8.2 - Prob. 64E Ch. 8.2 - Prob. 65E Ch. 8.3 - Prob. 1PQ Ch. 8.3 - Prob. 2PQ Ch. 8.3 - Prob. 3PQ Ch. 8.3 - Prob. 4PQ Ch. 8.3 - Prob. 5PQ Ch. 8.3 - Prob. 1E Ch. 8.3 - Prob. 2E Ch. 8.3 - Prob. 3E Ch. 8.3 - Prob. 4E Ch. 8.3 - Prob. 5E Ch. 8.3 - Prob. 6E Ch. 8.3 - Prob. 7E Ch. 8.3 - Prob. 8E Ch. 8.3 - Prob. 9E Ch. 8.3 - Prob. 10E Ch. 8.3 - Prob. 11E Ch. 8.3 - Prob. 12E Ch. 8.3 - Prob. 13E Ch. 8.3 - Prob. 14E Ch. 8.3 - Prob. 15E Ch. 8.3 - Prob. 16E Ch. 8.3 - Prob. 17E Ch. 8.3 - Prob. 18E Ch. 8.3 - Prob. 19E Ch. 8.3 - Prob. 20E Ch. 8.3 - Prob. 21E Ch. 8.3 - Prob. 22E Ch. 8.3 - Prob. 23E Ch. 8.3 - Prob. 24E Ch. 8.3 - Prob. 25E Ch. 8.3 - Prob. 26E Ch. 8.3 - Prob. 27E Ch. 8.3 - Prob. 28E Ch. 8.3 - Prob. 29E Ch. 8.3 - Prob. 30E Ch. 8.4 - Prob. 1PQ Ch. 8.4 - Prob. 2PQ Ch. 8.4 - Prob. 3PQ Ch. 8.4 - Prob. 4PQ Ch. 8.4 - Prob. 5PQ Ch. 8.4 - Prob. 6PQ Ch. 8.4 - Prob. 1E Ch. 8.4 - Prob. 2E Ch. 8.4 - Prob. 3E Ch. 8.4 - Prob. 4E Ch. 8.4 - Prob. 5E Ch. 8.4 - Prob. 6E Ch. 8.4 - Prob. 7E Ch. 8.4 - Prob. 8E Ch. 8.4 - Prob. 9E Ch. 8.4 - Prob. 10E Ch. 8.4 - Prob. 11E Ch. 8.4 - Prob. 12E Ch. 8.4 - Prob. 13E Ch. 8.4 - Prob. 14E Ch. 8.4 - Prob. 15E Ch. 8.4 - Prob. 16E Ch. 8.4 - Prob. 17E Ch. 8.4 - Prob. 18E Ch. 8.4 - Prob. 19E Ch. 8.4 - Prob. 20E Ch. 8.4 - Prob. 21E Ch. 8.4 - Prob. 22E Ch. 8.4 - Prob. 23E Ch. 8.4 - Prob. 24E Ch. 8.4 - Prob. 25E Ch. 8.4 - Prob. 26E Ch. 8.4 - Prob. 27E Ch. 8.4 - Prob. 28E Ch. 8.4 - Prob. 29E Ch. 8.4 - Prob. 30E Ch. 8.4 - Prob. 31E Ch. 8.4 - Prob. 32E Ch. 8.4 - Prob. 33E Ch. 8.4 - Prob. 34E Ch. 8.4 - Prob. 35E Ch. 8.4 - Prob. 36E Ch. 8.4 - Prob. 37E Ch. 8.4 - Prob. 38E Ch. 8.4 - Prob. 39E Ch. 8.4 - Prob. 40E Ch. 8.4 - Prob. 41E Ch. 8.4 - Prob. 42E Ch. 8.4 - Prob. 43E Ch. 8.4 - Prob. 44E Ch. 8.4 - Prob. 45E Ch. 8.4 - Prob. 46E Ch. 8.4 - Prob. 47E Ch. 8.4 - Prob. 48E Ch. 8.4 - Prob. 49E Ch. 8.4 - Prob. 50E Ch. 8.4 - Prob. 51E Ch. 8 - Prob. 1CRE Ch. 8 - Prob. 2CRE Ch. 8 - Prob. 3CRE Ch. 8 - Prob. 4CRE Ch. 8 - Prob. 5CRE Ch. 8 - Prob. 6CRE Ch. 8 - Prob. 7CRE Ch. 8 - Prob. 8CRE Ch. 8 - Prob. 9CRE Ch. 8 - Prob. 10CRE Ch. 8 - Prob. 11CRE Ch. 8 - Prob. 12CRE Ch. 8 - Prob. 13CRE Ch. 8 - Prob. 14CRE Ch. 8 - Prob. 15CRE Ch. 8 - Prob. 16CRE Ch. 8 - Prob. 17CRE Ch. 8 - Prob. 18CRE Ch. 8 - Prob. 19CRE Ch. 8 - Prob. 20CRE Ch. 8 - Prob. 21CRE Ch. 8 - Prob. 22CRE Ch. 8 - Prob. 23CRE Ch. 8 - Prob. 24CRE Ch. 8 - Prob. 25CRE Ch. 8 - Prob. 26CRE Ch. 8 - Prob. 27CRE Ch. 8 - Prob. 28CRE

Knowledge Booster

$Calculus$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.

That p ( t ) satisfies the condition ∫ 0 ∞ p ( t ) d t = 1 for all r > 0 .

Solution Summary: The author explains that p(t) satisfies the condition for the function.

Concept explainers

Videos

To show:

That p(t) satisfies the condition ∫0∞p(t)dt=1 for all r>0.

Want to see the full answer?

Chapter 8 Solutions

That p ( t ) satisfies the condition ∫ 0 ∞ p ( t ) d t = 1 for all r &gt; 0 .

Solution Summary: The author explains that p(t) satisfies the condition for the function.

Concept explainers

Videos

To show: That p(t) satisfies the condition ∫0∞p(t)dt=1 for all r>0.

Want to see the full answer?

Chapter 8 Solutions

That p ( t ) satisfies the condition ∫ 0 ∞ p ( t ) d t = 1 for all r > 0 .

To show:

That p(t) satisfies the condition ∫0∞p(t)dt=1 for all r>0.