(a) Explanation Given: Radius of the roll, r = 7. 6 cm = 0 .076 m Moment of inertia of the roll, I = 3.3 × 10 − 3 kgm 2 Force applied on the roll, F = 3.5 N Time for which the force is applied, t = 1.3 s Friction torque acting on the roll, τ f = 0.11 Nm Formula used: The length of paper that unrolls can be found by the following relation, l = θ r Where, θ is the angular displacement of the roll during the given time. θ = ω 0 t + ( 1 2 ) α t 2 Where, ω o is the initial angular velocity of the roll (which is 0 in this case) and α is its angular acceleration. α = Net torque on the roll ( τ n e t ) Moment of inertia ( I ) Calculation: τ n e t = τ – τ f = ( F × r ) – τ f = ( 3 (b) To determine The length of paper that unrolls from the time the force is stopped to the time the roll has stopped moving.

7th Edition

ISBN: 9780321921741

Author: GIANCOLI

Publisher: PEARSON

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Chapter 8, Problem 96GP

(a)

To determine

The length of paper that unrolls during the time the force is applied.

(b)

To determine

The length of paper that unrolls from the time the force is stopped to the time the roll has stopped moving.

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Chapter 8, Problem 95GP

Chapter 9, Problem 1OQ

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