(a) Explanation Given: The probability ofa randomly selected warbler having length between a and b centimeters isgiven by, P ( a ≤ x ≤ b ) = 1 0.95 2 π ∫ a b e − ( x − 12.9 ) 2 1.805 d x . Calculation: As, the length of warbler should be 13 centimeters or greater. Therefore, the probability function must be, P ( 13 ≤ x ≤ ∞ ) = 1 0.95 2 π ∫ 13 ∞ e − ( x − 12.9 ) 2 1.805 d x To evaluate this integral, follow the steps; Step 1: Select the [ M A T H ] key and then press 9 to select option 9 : f n I n t (b) To determine To calculate: The probability ofa randomly selected warbler having length between a and b centimeters is given by, P ( a ≤ x ≤ b ) = 1 0.95 2 π ∫ a b e − ( x − 12.9 ) 2 1.805 d x . The probability that a randomly selected warbler have length of 15 centimeters or greater.

Bundle: Calculus, 10th + WebAssign Printed Access Card for Larson/Edwards' Calculus, 10th Edition, Multi-Term

10th Edition

ISBN: 9781305718661

Author: Ron Larson, Bruce H. Edwards

Publisher: Cengage Learning

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Chapter 8, Problem 91RE

(a)

To determine

To calculate: The probability that a randomly selected warbler has a length between a and b centimeters is given as, $P(a≤x≤b)=10.952π∫abe−(x−12.9)21.805dx$ . The probability that a randomly selected warbler has a length of 13 centimeters or greater.

(b)

To determine

To calculate: The probability ofa randomly selected warbler having length between a and b centimeters is given by, $P(a≤x≤b)=10.952π∫abe−(x−12.9)21.805dx$ . The probability that a randomly selected warbler have length of 15 centimeters or greater.

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Chapter 8, Problem 90RE

Chapter 8, Problem 1PS

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Bundle: Calculus, 10th + WebAssign Printed Access Card for Larson/Edwards' Calculus, 10th Edition, Multi-Term

Ch. 8.1 - Choosing an Antiderivative In Exercises 3 and 4,...Ch. 8.1 - Choosing an Antiderivative In Exercises 3 and 4,...Ch. 8.1 - Prob. 3E Ch. 8.1 - Prob. 4E Ch. 8.1 - Choosing a Formula In Exercises 514, select the...Ch. 8.1 - Prob. 6E Ch. 8.1 - Choosing a Formula In Exercises 514, select the...Ch. 8.1 - Prob. 8E Ch. 8.1 - Prob. 9E Ch. 8.1 - Prob. 10E

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The probability that a randomly selected warbler has a length between a and b centimeters is given as, P ( a ≤ x ≤ b ) = 1 0.95 2 π ∫ a b e − ( x − 12.9 ) 2 1.805 d x . The probability that a randomly selected warbler has a length of 13 centimeters or greater.

Solution Summary: The author explains that the probability of a randomly selected warbler having the length of 13 centimeters or greater is given as, underset0.4581.