Chapter 8, Problem 8SA

Explanation of Solution

The computations proceed as follows:

1^st iteration of for loop:

    i =0

    alpha[0] = 0 * (0 + 1) = 0

    i % 2 equals 0 is true so

    alpha[4+i] = alpha[4 + 0] = alpha[4] = alpha[0] + i = 0 + 0 = 0

2^nd iteration of for loop:

    i = 1

    alpha[1] = 1 * (1 + 1) = 2

    i % 2 does not equal 0 and i % 3 does not equal 0 therefore

    alpha[4+i] = alpha[4+1] = alpha[5] = alpha[1] – alpha[1-1]

    = alpha[1] – alpha[0] = 2 – 0 = 2