for the given reaction, the masses of products formed from 30g of NH 3 and 175g of ClF 3 are needed to be determined. Concept introduction: Balanced chemical equation of a reaction is written according to law of conservation of mass. Mole ratio between the reactant and a product of a reaction are depends upon the coefficients of reactant and product in a balanced chemical equation. Equation for Number of moles of a substance, Number of moles = Given mass Molecular mass Equation for Number of grams of a substance from its number of moles is, Number of moles × Molecular mass in grams = Number of grams

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Answer 1

Question

Chapter 8, Problem 8.96QP

Interpretation Introduction

Interpretation: for the given reaction, the masses of products formed from 30g of $NH3$ and 175g of $ClF3$ are needed to be determined.

Concept introduction:

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Mole ratio between the reactant and a product of a reaction are depends upon the coefficients of reactant and product in a balanced chemical equation.

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Equation for Number of grams of a substance from its number of moles is,
$Number of moles × Molecular mass in grams = Number of grams$

Expert Solution & Answer

Answer to Problem 8.96QP

The mass of products formed in the given reaction are $24.7g N2 , 62.5g Cl2 and 106g HF$ .

Explanation of Solution

In given reaction diagram,

2 molecules of $ClF3$ reacts with two molecules of $NH3$ to form 1 molecule of $N2$ , 1 molecule of $Cl2$ , two molecules of $ClF3$ and six molecules of $HF$ .

So, the chemical equation for this reaction is,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Therefore,

The total number of each atoms in the reactant side should equal to the total number of each atoms in the product side.

So, in order to balance a chemical equation, the coefficients of compounds or atoms are needed to be changed in such a way that total number of each atoms in the reactant side and the total number of each atoms in the product side is to become equal.

Hence,

The above chemical equation is balanced;

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mass of $ClF3$ in the given reaction is given as $175g$ .

The mass of $NH3$ in the given reaction is given as $30g$ .

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Therefore,

The number of moles of $ClF3$ is,

$Number of moles = 175g92.45g = 1.893 mol$

The number of moles of $NH3$ is,

$Number of moles = 30g17.03g = 1.762 mol$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactants $ClF3$ and $NH3$ is 1:1.

The number of moles of $ClF3$ is found as $1.893 mol$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The limiting reactant of the reaction is $NH3$ , because it has less number of moles, so it consumes first in completely.

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $N2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $N2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $N2$ formed in the given reaction is,

$0.881 × 28.02g = 24.7g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $Cl2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $Cl2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $Cl2$ formed in the given reaction is,

$0.881 × 70.9g = 62.5g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $HF$ is $1:3$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $HF$ formed is,

$3 × 1.762 mol = 5.286 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $HF$ formed in the given reaction is,

$5.286 × 20.01g = 106g$

Conclusion

Conclusion

The masses of products formed from 30g of $NH3$ and 175g of $ClF3$ in the given reaction are determined according to the data’s given.

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Answer 2

Question

Chapter 8, Problem 8.96QP

Interpretation Introduction

Interpretation: for the given reaction, the masses of products formed from 30g of $NH3$ and 175g of $ClF3$ are needed to be determined.

Concept introduction:

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Mole ratio between the reactant and a product of a reaction are depends upon the coefficients of reactant and product in a balanced chemical equation.

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Equation for Number of grams of a substance from its number of moles is,
$Number of moles × Molecular mass in grams = Number of grams$

Expert Solution & Answer

Answer to Problem 8.96QP

The mass of products formed in the given reaction are $24.7g N2 , 62.5g Cl2 and 106g HF$ .

Explanation of Solution

In given reaction diagram,

2 molecules of $ClF3$ reacts with two molecules of $NH3$ to form 1 molecule of $N2$ , 1 molecule of $Cl2$ , two molecules of $ClF3$ and six molecules of $HF$ .

So, the chemical equation for this reaction is,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Therefore,

The total number of each atoms in the reactant side should equal to the total number of each atoms in the product side.

So, in order to balance a chemical equation, the coefficients of compounds or atoms are needed to be changed in such a way that total number of each atoms in the reactant side and the total number of each atoms in the product side is to become equal.

Hence,

The above chemical equation is balanced;

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mass of $ClF3$ in the given reaction is given as $175g$ .

The mass of $NH3$ in the given reaction is given as $30g$ .

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Therefore,

The number of moles of $ClF3$ is,

$Number of moles = 175g92.45g = 1.893 mol$

The number of moles of $NH3$ is,

$Number of moles = 30g17.03g = 1.762 mol$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactants $ClF3$ and $NH3$ is 1:1.

The number of moles of $ClF3$ is found as $1.893 mol$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The limiting reactant of the reaction is $NH3$ , because it has less number of moles, so it consumes first in completely.

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $N2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $N2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $N2$ formed in the given reaction is,

$0.881 × 28.02g = 24.7g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $Cl2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $Cl2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $Cl2$ formed in the given reaction is,

$0.881 × 70.9g = 62.5g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $HF$ is $1:3$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $HF$ formed is,

$3 × 1.762 mol = 5.286 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $HF$ formed in the given reaction is,

$5.286 × 20.01g = 106g$

Conclusion

Conclusion

The masses of products formed from 30g of $NH3$ and 175g of $ClF3$ in the given reaction are determined according to the data’s given.

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Answer 3

Question

Chapter 8, Problem 8.96QP

Interpretation Introduction

Interpretation: for the given reaction, the masses of products formed from 30g of $NH3$ and 175g of $ClF3$ are needed to be determined.

Concept introduction:

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Mole ratio between the reactant and a product of a reaction are depends upon the coefficients of reactant and product in a balanced chemical equation.

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Equation for Number of grams of a substance from its number of moles is,
$Number of moles × Molecular mass in grams = Number of grams$

Expert Solution & Answer

Answer to Problem 8.96QP

The mass of products formed in the given reaction are $24.7g N2 , 62.5g Cl2 and 106g HF$ .

Explanation of Solution

In given reaction diagram,

2 molecules of $ClF3$ reacts with two molecules of $NH3$ to form 1 molecule of $N2$ , 1 molecule of $Cl2$ , two molecules of $ClF3$ and six molecules of $HF$ .

So, the chemical equation for this reaction is,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Therefore,

The total number of each atoms in the reactant side should equal to the total number of each atoms in the product side.

So, in order to balance a chemical equation, the coefficients of compounds or atoms are needed to be changed in such a way that total number of each atoms in the reactant side and the total number of each atoms in the product side is to become equal.

Hence,

The above chemical equation is balanced;

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mass of $ClF3$ in the given reaction is given as $175g$ .

The mass of $NH3$ in the given reaction is given as $30g$ .

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Therefore,

The number of moles of $ClF3$ is,

$Number of moles = 175g92.45g = 1.893 mol$

The number of moles of $NH3$ is,

$Number of moles = 30g17.03g = 1.762 mol$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactants $ClF3$ and $NH3$ is 1:1.

The number of moles of $ClF3$ is found as $1.893 mol$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The limiting reactant of the reaction is $NH3$ , because it has less number of moles, so it consumes first in completely.

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $N2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $N2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $N2$ formed in the given reaction is,

$0.881 × 28.02g = 24.7g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $Cl2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $Cl2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $Cl2$ formed in the given reaction is,

$0.881 × 70.9g = 62.5g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $HF$ is $1:3$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $HF$ formed is,

$3 × 1.762 mol = 5.286 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $HF$ formed in the given reaction is,

$5.286 × 20.01g = 106g$

Conclusion

Conclusion

The masses of products formed from 30g of $NH3$ and 175g of $ClF3$ in the given reaction are determined according to the data’s given.

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Answer 4

Question

Chapter 8, Problem 8.96QP

Interpretation Introduction

Interpretation: for the given reaction, the masses of products formed from 30g of $NH3$ and 175g of $ClF3$ are needed to be determined.

Concept introduction:

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Mole ratio between the reactant and a product of a reaction are depends upon the coefficients of reactant and product in a balanced chemical equation.

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Equation for Number of grams of a substance from its number of moles is,
$Number of moles × Molecular mass in grams = Number of grams$

Expert Solution & Answer

Answer to Problem 8.96QP

The mass of products formed in the given reaction are $24.7g N2 , 62.5g Cl2 and 106g HF$ .

Explanation of Solution

In given reaction diagram,

2 molecules of $ClF3$ reacts with two molecules of $NH3$ to form 1 molecule of $N2$ , 1 molecule of $Cl2$ , two molecules of $ClF3$ and six molecules of $HF$ .

So, the chemical equation for this reaction is,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Therefore,

The total number of each atoms in the reactant side should equal to the total number of each atoms in the product side.

So, in order to balance a chemical equation, the coefficients of compounds or atoms are needed to be changed in such a way that total number of each atoms in the reactant side and the total number of each atoms in the product side is to become equal.

Hence,

The above chemical equation is balanced;

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mass of $ClF3$ in the given reaction is given as $175g$ .

The mass of $NH3$ in the given reaction is given as $30g$ .

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Therefore,

The number of moles of $ClF3$ is,

$Number of moles = 175g92.45g = 1.893 mol$

The number of moles of $NH3$ is,

$Number of moles = 30g17.03g = 1.762 mol$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactants $ClF3$ and $NH3$ is 1:1.

The number of moles of $ClF3$ is found as $1.893 mol$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The limiting reactant of the reaction is $NH3$ , because it has less number of moles, so it consumes first in completely.

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $N2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $N2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $N2$ formed in the given reaction is,

$0.881 × 28.02g = 24.7g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $Cl2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $Cl2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $Cl2$ formed in the given reaction is,

$0.881 × 70.9g = 62.5g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $HF$ is $1:3$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $HF$ formed is,

$3 × 1.762 mol = 5.286 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $HF$ formed in the given reaction is,

$5.286 × 20.01g = 106g$

Conclusion

Conclusion

The masses of products formed from 30g of $NH3$ and 175g of $ClF3$ in the given reaction are determined according to the data’s given.

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Answer 5

Chapter 8, Problem 8.96QP

Interpretation Introduction

Interpretation: for the given reaction, the masses of products formed from 30g of $NH3$ and 175g of $ClF3$ are needed to be determined.

Concept introduction:

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Mole ratio between the reactant and a product of a reaction are depends upon the coefficients of reactant and product in a balanced chemical equation.

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Equation for Number of grams of a substance from its number of moles is,
$Number of moles × Molecular mass in grams = Number of grams$

Expert Solution & Answer

Answer to Problem 8.96QP

The mass of products formed in the given reaction are $24.7g N2 , 62.5g Cl2 and 106g HF$ .

Explanation of Solution

In given reaction diagram,

2 molecules of $ClF3$ reacts with two molecules of $NH3$ to form 1 molecule of $N2$ , 1 molecule of $Cl2$ , two molecules of $ClF3$ and six molecules of $HF$ .

So, the chemical equation for this reaction is,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Therefore,

The total number of each atoms in the reactant side should equal to the total number of each atoms in the product side.

So, in order to balance a chemical equation, the coefficients of compounds or atoms are needed to be changed in such a way that total number of each atoms in the reactant side and the total number of each atoms in the product side is to become equal.

Hence,

The above chemical equation is balanced;

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mass of $ClF3$ in the given reaction is given as $175g$ .

The mass of $NH3$ in the given reaction is given as $30g$ .

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Therefore,

The number of moles of $ClF3$ is,

$Number of moles = 175g92.45g = 1.893 mol$

The number of moles of $NH3$ is,

$Number of moles = 30g17.03g = 1.762 mol$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactants $ClF3$ and $NH3$ is 1:1.

The number of moles of $ClF3$ is found as $1.893 mol$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The limiting reactant of the reaction is $NH3$ , because it has less number of moles, so it consumes first in completely.

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $N2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $N2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $N2$ formed in the given reaction is,

$0.881 × 28.02g = 24.7g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $Cl2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $Cl2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $Cl2$ formed in the given reaction is,

$0.881 × 70.9g = 62.5g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $HF$ is $1:3$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $HF$ formed is,

$3 × 1.762 mol = 5.286 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $HF$ formed in the given reaction is,

$5.286 × 20.01g = 106g$

Conclusion

Conclusion

The masses of products formed from 30g of $NH3$ and 175g of $ClF3$ in the given reaction are determined according to the data’s given.

Answer 6

Chapter 8, Problem 8.96QP

Interpretation Introduction

Interpretation: for the given reaction, the masses of products formed from 30g of $NH3$ and 175g of $ClF3$ are needed to be determined.

Concept introduction:

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Mole ratio between the reactant and a product of a reaction are depends upon the coefficients of reactant and product in a balanced chemical equation.

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Equation for Number of grams of a substance from its number of moles is,
$Number of moles × Molecular mass in grams = Number of grams$

Expert Solution & Answer

Answer to Problem 8.96QP

The mass of products formed in the given reaction are $24.7g N2 , 62.5g Cl2 and 106g HF$ .

Explanation of Solution

In given reaction diagram,

2 molecules of $ClF3$ reacts with two molecules of $NH3$ to form 1 molecule of $N2$ , 1 molecule of $Cl2$ , two molecules of $ClF3$ and six molecules of $HF$ .

So, the chemical equation for this reaction is,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Therefore,

The total number of each atoms in the reactant side should equal to the total number of each atoms in the product side.

So, in order to balance a chemical equation, the coefficients of compounds or atoms are needed to be changed in such a way that total number of each atoms in the reactant side and the total number of each atoms in the product side is to become equal.

Hence,

The above chemical equation is balanced;

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mass of $ClF3$ in the given reaction is given as $175g$ .

The mass of $NH3$ in the given reaction is given as $30g$ .

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Therefore,

The number of moles of $ClF3$ is,

$Number of moles = 175g92.45g = 1.893 mol$

The number of moles of $NH3$ is,

$Number of moles = 30g17.03g = 1.762 mol$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactants $ClF3$ and $NH3$ is 1:1.

The number of moles of $ClF3$ is found as $1.893 mol$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The limiting reactant of the reaction is $NH3$ , because it has less number of moles, so it consumes first in completely.

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $N2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $N2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $N2$ formed in the given reaction is,

$0.881 × 28.02g = 24.7g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $Cl2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $Cl2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $Cl2$ formed in the given reaction is,

$0.881 × 70.9g = 62.5g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $HF$ is $1:3$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $HF$ formed is,

$3 × 1.762 mol = 5.286 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $HF$ formed in the given reaction is,

$5.286 × 20.01g = 106g$

Conclusion

Conclusion

The masses of products formed from 30g of $NH3$ and 175g of $ClF3$ in the given reaction are determined according to the data’s given.

Answer 7

Chapter 8, Problem 8.96QP

Interpretation Introduction

Interpretation: for the given reaction, the masses of products formed from 30g of $NH3$ and 175g of $ClF3$ are needed to be determined.

Concept introduction:

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Mole ratio between the reactant and a product of a reaction are depends upon the coefficients of reactant and product in a balanced chemical equation.

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Equation for Number of grams of a substance from its number of moles is,
$Number of moles × Molecular mass in grams = Number of grams$

Answer 8

Expert Solution & Answer

Answer to Problem 8.96QP

The mass of products formed in the given reaction are $24.7g N2 , 62.5g Cl2 and 106g HF$ .

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

In given reaction diagram,

2 molecules of $ClF3$ reacts with two molecules of $NH3$ to form 1 molecule of $N2$ , 1 molecule of $Cl2$ , two molecules of $ClF3$ and six molecules of $HF$ .

So, the chemical equation for this reaction is,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

Balanced chemical equation of a reaction is written according to law of conservation of mass.

Therefore,

The total number of each atoms in the reactant side should equal to the total number of each atoms in the product side.

So, in order to balance a chemical equation, the coefficients of compounds or atoms are needed to be changed in such a way that total number of each atoms in the reactant side and the total number of each atoms in the product side is to become equal.

Hence,

The above chemical equation is balanced;

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mass of $ClF3$ in the given reaction is given as $175g$ .

The mass of $NH3$ in the given reaction is given as $30g$ .

Equation for Number of moles of a substance,

$Number of moles = Given massMolecular mass$

Therefore,

The number of moles of $ClF3$ is,

$Number of moles = 175g92.45g = 1.893 mol$

The number of moles of $NH3$ is,

$Number of moles = 30g17.03g = 1.762 mol$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactants $ClF3$ and $NH3$ is 1:1.

The number of moles of $ClF3$ is found as $1.893 mol$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The limiting reactant of the reaction is $NH3$ , because it has less number of moles, so it consumes first in completely.

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $N2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $N2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $N2$ formed in the given reaction is,

$0.881 × 28.02g = 24.7g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $Cl2$ is $1:12$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $Cl2$ formed is,

$12 × 1.762 mol = 0.881 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $Cl2$ formed in the given reaction is,

$0.881 × 70.9g = 62.5g$

The balanced equation of the reaction is found as,

$2ClF3 + 2NH3 → N2 + Cl2 + 6HF$

The mole ratio between reactant $NH3$ and product $HF$ is $1:3$ .

The number of moles of $NH3$ is found as $1.762 mol$ .

Therefore,

The number of moles of $HF$ formed is,

$3 × 1.762 mol = 5.286 mol$

Equation for Number of grams of a substance from its number of moles is,

$Number of moles × Molecular mass in grams = Number of grams$

Therefore,

The mass of $HF$ formed in the given reaction is,

$5.286 × 20.01g = 106g$

Answer 12

Conclusion

Conclusion

The masses of products formed from 30g of $NH3$ and 175g of $ClF3$ in the given reaction are determined according to the data’s given.

Answer 13

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Answer to Problem 8.96QP

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