a.
To determine:
The initial volume in liters that is required to prepare given solution.
Concept introduction:
The final concentration of diluted solution is always less than initial concentration of a stock solution, whereas final volume of diluted solution is more than that of initial volume of a concentrated solution. Stock solution is the concentrated solution prepared from a solute and solvent. It is diluted further to prepare the actual solution with high accuracy.
In the given problem, final volume and two concentrations are given. The initial volume of solution is calculated by the formula,
b.
To determine:
The initial volume in liters that is required to prepare given solution.
Concept introduction:
The final concentration of diluted solution is always less than initial concentration of a stock solution, whereas final volume of diluted solution is more than that of initial volume of a concentrated solution. Stock solution is the concentrated solution prepared from a solute and solvent. It is diluted further to prepare the actual solution with high accuracy.
In the given problem, final volume and two concentrations are given. The initial volume of solution is calculated by the formula,

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Chapter 8 Solutions
EBK LABORATORY MANUAL FOR GENERAL, ORGA
- TRANSMITTANCE เบบ Please identify the one structure below that is consistent with the 'H NMR and IR spectra shown and draw its complete structure in the box below with the protons alphabetically labeled as shown in the NMR spectrum and label the IR bands, including sp³C-H and sp2C-H stretch, indicated by the arrows. D 4000 OH LOH H₂C CH3 OH H₂C OCH3 CH3 OH 3000 2000 1500 HAVENUMBERI-11 1000 LOCH3 Draw your structure below and label its equivalent protons according to the peak labeling that is used in the NMR spectrum in order to assign the peaks. Integrals indicate number of equivalent protons. Splitting patterns are: s=singlet, d=doublet, m-multiplet 8 3Hb s m 1Hd s 3Hf m 2Hcd 2Had 1He 鄙视 m 7 7 6 5 4 3 22 500 T 1 0arrow_forwardRelative Transmittance 0.995 0.99 0.985 0.98 Please draw the structure that is consistent with all the spectral data below in the box and alphabetically label the equivalent protons in the structure (Ha, Hb, Hc ....) in order to assign all the proton NMR peaks. Label the absorption bands in the IR spectrum indicated by the arrows. INFRARED SPECTRUM 1 0.975 3000 2000 Wavenumber (cm-1) 1000 Structure with assigned H peaks 1 3 180 160 140 120 100 f1 (ppm) 80 60 40 20 0 C-13 NMR note that there are 4 peaks between 120-140ppm Integral values equal the number of equivalent protons 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 fl (ppm)arrow_forwardCalculate the pH of 0.0025 M phenol.arrow_forward
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- The Ka for sodium dihydrogen phosphate is 6.32 x 10-8. Find the pH of a buffer made from 0.15 M H2PO4- and 0.25 M HPO42- .arrow_forwardThe Ka for lactic acid is 1.4 x 10-4. Find the pH of a buffer made from 0.066 M lactic acid and 0.088 M sodium lactate.arrow_forwardZaitsev's Rule 3) (a) Rank the following alkenes in order of decreasing stability. most stable A B C D > > > (b) Rank the following carbocations in order of decreasing stability least stable B C Darrow_forward
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