Chapter 8, Problem 8.79SP

(a)

Interpretation Introduction

To determine: The two organic products that are generated when the trialkylborane is oxidized with ${\text{H}}_2{\text{O}}_2/\text{NaOH}$.

Interpretation: The two organic products that are generated when the trialkylborane is oxidized with ${\text{H}}_2{\text{O}}_2/\text{NaOH}$ and the structure of diene is to be stated.

Concept introduction: Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows anti-markovinokov’s rule.

Anti markovinokov’s rule states that the positive part of halogen acid gets attached to that carbon atom in $\text{C=C}$ bond which carries minimum number of hydrogen atoms and the negative part of halogen acid will get attached to that carbon atom in $\text{C=C}$ bond which has maximum number of hydrogen atoms.

(b)

Interpretation Introduction

To determine: The structure of the diene across which addition of ${\text{BH}}_{\text{3}}$ synthesizes $\text{9}-\text{BBM}$.

Interpretation: The structure of the diene across which addition of ${\text{BH}}_{\text{3}}$ synthesises $\text{9}-\text{BBM}$ is to be drawn.

Concept introduction: Hydroboration reaction is a two step reaction, which involves conversion of alkene into alcohol. This type of reaction follows anti-markovinokov’s rule.

Anti markovinokov’s rule states that the positive part of halogen acid gets attached to that carbon atom in $\text{C=C}$ bond which carries minimum number of hydrogen atoms and the negative part of halogen acid will get attached to that carbon atom in $\text{C=C}$ bond which has maximum number of hydrogen atoms.