Principles of General Organic & Biological Chemistry
Principles of General Organic & Biological Chemistry
2nd Edition
ISBN: 9780077633721
Author: Janice Smith
Publisher: Mcgraw-hill Higher Education (us)
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Chapter 8, Problem 8.55AP

(a)

Interpretation Introduction

Interpretation:

The acid, base, conjugate acid and conjugate base of the reaction has to be labeled.

The given equation is,

  HI(g)+NH3(g)NH4+(aq)+I-(aq)

Concept Introduction:

Bronsted-Lowry Acids:  A Bronsted-Lowry acid is proton donor and contains a hydrogen atom.  It may be a neutral molecule or may contain a net positive or negative charge.

Bronsted-Lowry Bases:  A Bronsted-Lowry base is a proton acceptor.  A base should contain a lone pair of electrons, which donates to form a new bond.  It can be neutral or can contain a negative charge.

Conjugate acid:  A conjugate acid is the product formed by a gain of a proton by a base.  The conjugate acid of the base B will be HB+.

Conjugate base:  A conjugate base is the product formed by a loss of proton from an acid.  The conjugate base of the acid A will be A-.

(a)

Expert Solution
Check Mark

Answer to Problem 8.55AP

The acid in the reaction is HI.

The conjugate base of the acid is I-.

The base in the reaction is NH3.

The conjugate acid of the base is NH4+.

Explanation of Solution

Acid loses a proton and forms conjugate base.

Base accepts a proton and forms conjugate acid.

The given reaction is,

  HI(g)+NH3(g)NH4+(aq)+I-(aq)

Hydroiodic acid loses its proton to form iodide.  Ammonia gains a proton to form ammonium ion.

  HI(g)+NH3(g)NH4+(aq)+I-(aq)AcidBaseConjugateConjugateAcidBase

(b)

Interpretation Introduction

Interpretation:

The acid, base, conjugate acid and conjugate base of the reaction has to be labeled.

The given equation is,

  HCOOH(l)+H2O(l)H3O+(aq)+HCOO-(aq)

Concept Introduction:

Refer to part (a).

(b)

Expert Solution
Check Mark

Answer to Problem 8.55AP

The acid in the reaction is HCOOH.

The conjugate base of the acid is HCOO-.

The base in the reaction is H2O.

The conjugate acid of the base is H3O+.

Explanation of Solution

The given reaction is,

  HCOOH(l)+H2O(l)H3O+(aq)+HCOO-(aq)

Formic acid loses a proton to form formate ion.  Water gains a proton and forms hydronium ion.

  HCOOH(l)+H2O(l)H3O+(aq)+HCOO-(aq)AcidBaseConjugateConjugateAcidBase

(c)

Interpretation Introduction

Interpretation:

The acid, base, conjugate acid and conjugate base of the reaction has to be labeled.

The given equation is,

  HSO4-(aq)+H2O(l)H2SO4(aq)+OH-(aq)

Concept Introduction:

Refer to part (a).

(c)

Expert Solution
Check Mark

Answer to Problem 8.55AP

The acid in the reaction is H2O.

The conjugate base of the acid is OH-.

The base in the reaction is HSO4-.

The conjugate acid of the base is H2SO4.

Explanation of Solution

The given reaction is,

  HSO4-(aq)+H2O(l)H2SO4(aq)+OH-(aq)

Hydrogen sulphate (HSO4-) gains a proton and forms sulphuric acid.  Water loses a proton to form hydronium ion.

  HSO4-(aq)+H2O(l)H2SO4(aq)+OH-(aq)BaseWaterConjugateConjugateAcidBase

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please solve this question. It is very sensentive with spelling and characters so if it is "no errors" please be specific.    thanks!
Don't used hand raiting and don't used Ai solution
H2(g) + I2(g) ⇔ 2HI(g) Using the above equilibrium, find the equilibrium concentration of H2 if the intial concentration of both H2 and I2 are 2.0. K at this temperature is 55.64.

Chapter 8 Solutions

Principles of General Organic & Biological Chemistry

Ch. 8.2 - When ascorbic acid (vitamin C, molecular formula...Ch. 8.3 - Prob. 8.12PCh. 8.3 - Prob. 8.13PCh. 8.3 - Prob. 8.14PCh. 8.3 - Prob. 8.15PCh. 8.4 - Calculate the value of [OH] from the given [H3O+]...Ch. 8.4 - Calculate the value of [H3O+] from the given [OH]...Ch. 8.4 - Calculate the value of [H3O+] and [OH] in each...Ch. 8.5 - Convert each H3O+ concentration to a pH value. a....Ch. 8.5 - What H3O+ concentration corresponds to each pH...Ch. 8.5 - Prob. 8.21PCh. 8.5 - Prob. 8.22PCh. 8.6 - Write a balanced equation for each acidbase...Ch. 8.6 - Prob. 8.24PCh. 8.6 - Prob. 8.25PCh. 8.6 - Write a balanced equation for the reaction of...Ch. 8.7 - Prob. 8.27PCh. 8.7 - Prob. 8.28PCh. 8.8 - Prob. 8.29PCh. 8.8 - Prob. 8.30PCh. 8 - Draw the structure of the conjugate base of each...Ch. 8 - Draw the structure of the conjugate base of each...Ch. 8 - (a) Which of the following represents a strong...Ch. 8 - Prob. 8.34UKCCh. 8 - Identify the acid, base, conjugate acid, and...Ch. 8 - Prob. 8.36UKCCh. 8 - Prob. 8.37UKCCh. 8 - Prob. 8.38UKCCh. 8 - Prob. 8.39UKCCh. 8 - Prob. 8.40UKCCh. 8 - If a urine sample has a pH of 5.90, calculate the...Ch. 8 - Prob. 8.42UKCCh. 8 - Prob. 8.43UKCCh. 8 - Prob. 8.44UKCCh. 8 - Consider a buffer prepared from the weak acid HNO2...Ch. 8 - Prob. 8.46UKCCh. 8 - Prob. 8.47APCh. 8 - Prob. 8.48APCh. 8 - Prob. 8.49APCh. 8 - Prob. 8.50APCh. 8 - Prob. 8.51APCh. 8 - Prob. 8.52APCh. 8 - Draw the conjugate base of each acid. a. HNO2 b....Ch. 8 - Draw the conjugate base of each acid. a. H3O+ b....Ch. 8 - Prob. 8.55APCh. 8 - Prob. 8.56APCh. 8 - Prob. 8.57APCh. 8 - Like H2O, H2PO4 is amphoteric. (a) Draw the...Ch. 8 - Prob. 8.59APCh. 8 - Prob. 8.60APCh. 8 - Prob. 8.61APCh. 8 - Prob. 8.62APCh. 8 - Prob. 8.63APCh. 8 - Prob. 8.64APCh. 8 - Prob. 8.65APCh. 8 - Prob. 8.66APCh. 8 - Prob. 8.67APCh. 8 - Prob. 8.68APCh. 8 - Calculate the value of [OH] from the given [H3O+]...Ch. 8 - Calculate the value of [OH] from the given [H3O+]...Ch. 8 - Calculate the value of [H3O+] from the given [OH]...Ch. 8 - Prob. 8.72APCh. 8 - Prob. 8.73APCh. 8 - Calculate the pH from each H3O+ concentration...Ch. 8 - Prob. 8.75APCh. 8 - Prob. 8.76APCh. 8 - What are the concentrations of H3O+ and OH in...Ch. 8 - Prob. 8.78APCh. 8 - Prob. 8.79APCh. 8 - Prob. 8.80APCh. 8 - Prob. 8.81APCh. 8 - Prob. 8.82APCh. 8 - Prob. 8.83APCh. 8 - Prob. 8.84APCh. 8 - Prob. 8.85APCh. 8 - Prob. 8.86APCh. 8 - Prob. 8.87APCh. 8 - Prob. 8.88APCh. 8 - Consider a weak acid H2A and its conjugate base...Ch. 8 - Consider a weak acid H2A and its conjugate base...Ch. 8 - Prob. 8.91APCh. 8 - Prob. 8.92APCh. 8 - Prob. 8.93APCh. 8 - Prob. 8.94APCh. 8 - The optimum pH of a swimming pool is 7.50....Ch. 8 - A sample of rainwater has a pH of 4.18. (a)...Ch. 8 - Prob. 8.97APCh. 8 - Prob. 8.98APCh. 8 - Prob. 8.99APCh. 8 - Explain why a lake on a bed of limestone is...Ch. 8 - Prob. 8.101CP
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