Architectural Drafting and Design (MindTap Course List)
Architectural Drafting and Design (MindTap Course List)
7th Edition
ISBN: 9781285165738
Author: Alan Jefferis, David A. Madsen, David P. Madsen
Publisher: Cengage Learning
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Chapter 8, Problem 8.14Q
To determine

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Average Shear Stress BASIC FORMULAS General Shear Stress fv lb Shear Flow Flexural or Bending Stress VQ q Fb Mc M 1 Sx dtw fy-shear stress V = shear capacity d depth of the section tw = web thickness Radius of Gyration Q-statical moment of area Imoment of inertia of whole section b value of width where you cut Note: can be used to solve maximum shear stress Note: Maximum Shear Stress is located at the neutral axis (smallest width) Section Modulus Sx=x NOTE: If not given Fy 248 MPa for A36 Steel Fu-400 MPa for A36 Steel Es-200,000 MPa fb flexural or bending stress M-moment capacity I-Moment of Inertia of the whole section Sx-section modulus fy actual shear stress (from loads) Fv allowable shear stress (from NSCP) fv-Fv; safe and economical Vmax= P2 P Mmax = COMMON LOADINGS AND SUPPORTS PPP L/4 4↓1 44 L/4 PL PL Ymax = 48E1 Vmax = 1.5P Mmax = 22 PL 19PL Ymax = 384E1 P P [[ P P WL Vmax= 2 Mmax = P P L/3 ↓ L/3 ↓ L/3 WL' Swi Ymax = 384 ΕΙ PL 23PL Vmax = P Mmax = 이 Ymax =. 648E1
Consider, M people (aka pax) who want to travel by car from O to D. They all start working at D at Q (e.g., Q-8am). If a person departs at time t, assume the time needed to go from O to D is given by c(t)=A+Bx(t), where x(t) is the flow of people departing at time t [car/unit of time]. In addition, a is the penalty for being early at work (E(t) is how early the person arrived when departing at time t), and ẞ is the penalty for being late at work (L(t) is how late the person arrived when departing at time t). Assume 0 < a < 1 < ß. Further assume the departure time choice problem under the equilibrium conditions. Prove that the arrival time of people who depart when most of the M people start their trips is equal to Q.
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Architectural Drafting and Design (MindTap Course...
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