Explanation Given info: 45 specimens of a particular type of brick was collected and the average unrestrained compressive strength was measured. The average is 3,107 psi. The standard deviation is 188. Calculation: Here, the sample size is large enough to assume normality condition. Hence, z test can be used. Step 1: Parameter of interest: Let μ be the true average unrestrained compressive strength. Step 2: Null hypothesis: H 0 : μ = 3 , 200 That is, the average unrestrained compressive strength is 3,200. Step 3: Alternative hypothesis: H a : μ < 3 , 200 That is, the average unrestrained compressive strength is less than 3,200. Step 4: Test statistic: Software procedure: Step by step procedure to obtain the test-statistic value using the MINITAB software: Choose Stat > Basic Statistics > 1-Sample z . In Summarized data, enter the sample size as 45 and mean as 3,107 In Standard deviation , enter 188 In Perform hypothesis test, enter the test mean as 1.75 Check Options ; enter Confidence level as 99.9 . Choose less than in alternative

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Author: DEVORE

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Chapter 8, Problem 69SE

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Test whether the data strongly indicate that the true average unrestrained compressive strength is less than the design value of 3200.

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Chapter 8, Problem 68SE

Chapter 8, Problem 70SE

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Chapter 8 Solutions

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Test whether the data strongly indicate that the true average unrestrained compressive strength is less than the design value of 3200.

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Chapter 8 Solutions