Chapter 8, Problem 63P

Interpretation Introduction

Interpretation: The stereoisomer of $\text{1, 2, 3, 4, 5, 6-hexachlorocyclohexane}$ that reacts $7000$ times more slowly than any of the other isomer in an $\text{E2}$ elimination is to be drawn and the reason for the same is to be stated.

Concept introduction: The one-step bimolecular elimination reaction that favors the removal of a proton by a base from carbon adjacent to the leaving group that results in the formation of a carbocation is termed as $\text{E2}$ elimination reaction. The formation of a double bond takes place simultaneously through the carbocation to form an alkene as the desired product. In case of $\text{E2}$ elimination, the anti-periplanar geometry should exist between the halogen and the proton that is being abstracted.