
Chemistry In Focus
7th Edition
ISBN: 9781337399692
Author: Tro, Nivaldo J.
Publisher: Cengage Learning,
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Chapter 8, Problem 55E
Interpretation Introduction
Interpretation:
The time required for the decay of technetium-99m to one eighth of its initial amount with a half-life of 6.0 hours is to be calculated.
Concept Introduction:
The half-life of a radioactive substance is the time in which the amount of the given radioactive substance is reduced to half of its initial value. The half-life for a given substance is represented by t1/2.
After each half-life period, the amount of the substance is reduced to half of the initial number.
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For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box.
Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below.
Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first
stable product you expect to form in solution.
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✗MgBr
?
O
CI
Will the first product that forms in this reaction
create a new C-C bond?
Yes
No
•
?
Will the first product that forms in this reaction
create a new CC bond?
Yes
No
×
: ☐
X
Predict the major products of this organic reaction:
OH
NaBH4
H
?
CH3OH
Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry.
Click and drag to start drawing a
structure.
☐ :
S
Predict the major products of this organic reaction:
1. LIAIHA
2. H₂O
?
Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry.
Click and drag to start drawing a
structure.
X
: ☐
Chapter 8 Solutions
Chemistry In Focus
Ch. 8 - Prob. 8.1YTCh. 8 - Prob. 8.2YTCh. 8 - Prob. 8.3YTCh. 8 - Prob. 8.4YTCh. 8 - Prob. 8.5YTCh. 8 - Prob. 1SCCh. 8 - Prob. 2SCCh. 8 - Prob. 3SCCh. 8 - Prob. 4SCCh. 8 - Prob. 5SC
Ch. 8 - Prob. 6SCCh. 8 - Prob. 7SCCh. 8 - Prob. 1ECh. 8 - Prob. 2ECh. 8 - Prob. 3ECh. 8 - Prob. 4ECh. 8 - Prob. 5ECh. 8 - Prob. 6ECh. 8 - Prob. 7ECh. 8 - Prob. 8ECh. 8 - Prob. 9ECh. 8 - Prob. 10ECh. 8 - Prob. 11ECh. 8 - Prob. 12ECh. 8 - Prob. 13ECh. 8 - Prob. 14ECh. 8 - Prob. 15ECh. 8 - Prob. 16ECh. 8 - Prob. 17ECh. 8 - Prob. 18ECh. 8 - Prob. 19ECh. 8 - Prob. 20ECh. 8 - Prob. 21ECh. 8 - Prob. 22ECh. 8 - Prob. 23ECh. 8 - Prob. 24ECh. 8 - Prob. 25ECh. 8 - Prob. 26ECh. 8 - Prob. 27ECh. 8 - Prob. 28ECh. 8 - Prob. 29ECh. 8 - Prob. 30ECh. 8 - Prob. 31ECh. 8 - Prob. 32ECh. 8 - Prob. 33ECh. 8 - Prob. 34ECh. 8 - Prob. 35ECh. 8 - Prob. 36ECh. 8 - Prob. 37ECh. 8 - Prob. 38ECh. 8 - Prob. 39ECh. 8 - Prob. 40ECh. 8 - Prob. 42ECh. 8 - Prob. 43ECh. 8 - Prob. 44ECh. 8 - Prob. 45ECh. 8 - Prob. 46ECh. 8 - Prob. 47ECh. 8 - Prob. 48ECh. 8 - Prob. 49ECh. 8 - Prob. 50ECh. 8 - Prob. 51ECh. 8 - Prob. 52ECh. 8 - Prob. 53ECh. 8 - Prob. 54ECh. 8 - Prob. 55ECh. 8 - Prob. 56ECh. 8 - Prob. 57ECh. 8 - Prob. 58ECh. 8 - Prob. 59ECh. 8 - Prob. 62ECh. 8 - Prob. 63ECh. 8 - Prob. 64ECh. 8 - Prob. 65ECh. 8 - Prob. 66ECh. 8 - Prob. 67ECh. 8 - Prob. 68ECh. 8 - Prob. 69E
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